Hi Prove that if , where and are positive integers, and is a positive odd integer, then Result due to Gauss or Euler... I can't remember... more likely to Gauss
Follow Math Help Forum on Facebook and Google+
Isn't it ? If it is correct , then ... since Therefore , Finally , sub. x into 2
The fact that is odd means that the expression will end in Hence
Is it true for all positive integers ?? Therefore , If , then .
Originally Posted by simplependulum Is it true for all positive integers ?? Therefore , If , then . Yup, I’d say that’s true.
Originally Posted by simplependulum Isn't it ? If it is correct , then ... since Therefore , Finally , sub. x into 2 I don't understand your reasoning Yup, that's the key step Here is how I did : Because is odd, we have And since the sum is an integer, we're done
View Tag Cloud