Prove that

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- May 27th 2009, 11:45 PMsimplependulumA question about Riemann Zeta function
Prove that

- May 28th 2009, 06:41 AMNonCommAlg
- May 28th 2009, 10:42 AMPaulRS
Let's start with the Fourier Series (It may also be done in other ways, see ):

- integrating again-

Repeating the process we get:

for

Now set:

Here - May 31st 2009, 12:26 AMsimplependulum
Excellent ! I couldn't imgaine that there is one more solution for this question .