$\displaystyle 2y e^{y/x} \frac{dy}{{dx}} - 2x - y = 0$

I'm not sure how difficult you guys at this forum might find this. It took me a long long long time to figure out (I am not a math major). Should need at least two substitutions.

(The solution, in implicit form, is $\displaystyle y^2 - x^2 e^{y/x} = C$).