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- December 11th 2006, 05:42 AM #1

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## Question 10

**Im**PerfectHacker has requested that I post this problem - allegedly because

he does not understand it. It does not look too difficult to me, though a bit

fiddly.

RonL

One day it started snowing at a heavy and steady rate. A snowplough

started out at noon, going 2 km the first hour and 1 km the second hour.

What time did it start snowing?

.

- December 11th 2006, 05:56 AM #2

- December 11th 2006, 05:58 AM #3

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- December 11th 2006, 06:00 AM #4

- December 11th 2006, 06:56 AM #5
Hello,

where do you live?

But nevertheless have a look here: Snowploughs

EB

- December 11th 2006, 07:08 AM #6

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- December 11th 2006, 07:17 AM #7

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I presume you know what snow is.

A snowplough is a vehicle used for clearing snow from railways or roads

using something vaguely like a bulldozer blade.

I would upload a picture, but there seems to be something wrong with

the upload system at present, so lets try this

Google Image Result for http://upload.wikimedia.org/wikipedia/en/thumb/d/d3/Snowplow.jpg/300px-Snowplow.jpg

RonL

- December 11th 2006, 01:03 PM #8

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- December 11th 2006, 08:38 PM #9

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- December 11th 2006, 08:54 PM #10

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- December 12th 2006, 03:59 AM #11

- December 12th 2006, 04:31 AM #12

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Ahh.. but there is my dear squark there is..

On a serious note I make it three unknowns (sweep rate, snow accumulation rate, and time at which snow started)

and three equations, swept path at noon, ay 13:00, and at 14:00. That does not guarantee that a solution can be

found it should at least give hope that it can be found.

RonL

- December 12th 2006, 07:04 AM #13

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- December 12th 2006, 07:14 AM #14
I have heard of it. I tackled it years ago in DE.

What's interesting is that the answer is related to the golden ratio.

[tex]\frac{\sqrt{5}-1}{2}[/tex]

This equals about 37 minutes. When subtracted from 12 noon, one gets

11:23 am.

I can't seem to get LaTex to work for some reason. I just get a blank screen when I try to preview.

- December 12th 2006, 10:04 AM #15