Prove that for all . Not very hard, but I wonder to see if there will be nice solutions.
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Originally Posted by bkarpuz Prove that for all . Not very hard, but I wonder to see if there will be nice solutions. is equivalent to
Originally Posted by NonCommAlg is equivalent to Of course this is the most simple proof. And still waiting for interesting solutions.
If then .
Originally Posted by halbard If then . My own solution was also similar. Just set for , and show that for all . Since is even, we have for all .
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