Rearrange the 3x3 block of squares below to create another 3x3 block in which each pair of adjacent sides in neighboring squares has a sum of 9. You are allowed to rotate the squares and may change a square's position in the 3x3 block. However, pieces cannot be flipped over.
hint for you: The letters in the middle of each square have only been inserted to assist that in determining whether or not a proposed solution is correct.
Are you sure that the image is correct? No one has post an answer yet... and I keep on running into endless loops trying to solve this.
Should there be 2 identical squares H=D? Changning one element in one of those and I have a solution ....:D