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Math Help - come back with puzzle

  1. #1
    Newbie
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    come back with puzzle

    Live is like a puzzle !

    You are equipped with a single 2, 3, 23, and 32 along with the ability to combine them using addition, subtraction, multiplication, division, and exponentiation.

    Your job is to create all of the integers from 33 to 50 (inclusive).

    You may use any number of parentheses to control the order of operations and need not use all four numbers each time. Remember, no number can be used twice.

    For example: 24 = 32 - 2^3
    (where 2^3 means 2 to the 3rd power)
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  2. #2
    Member
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    Nice puzzle.

    33 = 32 - 2 + 3
    34 = 32 + 2
    35 = 32 + 3
    36 = (32 / 2) - 3 + 23
    37 = 32 + 3 + 2
    38 = 32 + (3 x 2)
    39 = ((23 - 2) / 3) + 32
    40 = (2 ^ 3) + 32
    41 = (3 ^ 2) + 32
    42 = 32 + ((23 - 3) / 2)
    43 = (23 x 2) - 3
    44 = (32 x 2) - 23 + 3
    45 = ((23 + 3) / 2) + 32
    46 = 23 + 32 - (3 ^ 2)
    47 = 23 + 32 - (2 ^ 3)
    48 = 32 x 3 / 2
    49 = 23 + 32 - (2 x 3)
    50 = 23 + 32 - 2 - 3
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  3. #3
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    Lexington, MA (USA)
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    Hello, distance!

    I got most of them . . . How far did you get?


    You are equipped with: 2, 3, 23, and 32 along with the ability to combine them
    using addition, subtraction, multiplication, division, and exponentiation.

    Your job is to create all of the integers from 33 to 50 (inclusive).

    You may use any number of parentheses to control the order of operations
    and need not use all four numbers. .No number can be used twice.

    \begin{array}{c|c}<br />
33 & \quad32 + (3-2) \\<br />
34 & \quad32 + 2 \\<br />
35 & \quad32 + 3 \\<br />
36 & \quad23 + \frac{32}{2} - 3 \\<br />
37 & \quad32 + 2 + 3 \\<br />
38 & \quad32 + (2\times3) \\ <br />
39 & \quad--- \\<br />
40 & \quad32 + 2^3 \\<br />
41 & \quad32 + 3^2 \\<br />
42 & \quad 23 + \frac{32}{2} + 3 \end{array}
    \begin{array}{c|c}<br />
43 & --- \\<br />
44 & (32\times2) - (23-3) \\<br />
45 & 32 + \frac{23+3}{2} \\<br />
46 & (23+32) - 3^2 \\<br />
47 & (23+32) - 2^3 \\<br />
48  & --- \\<br />
49 & (23+32) - (3\times2) \end{array}
    \begin{array}{c|c}50 & (23+32) - (2+3) \end{array}

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  4. #4
    A riddle wrapped in an enigma
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    39=\frac{23-2}{3}+32

    43=2(23)-3

    48=\frac{32}{2} \times 3
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  5. #5
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    You solved it...Great job
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