Mother, three daughters and 90 eggs

Mother has send her three daughters to sell totally 90 eggs on market.

She gave oldest and most brightest daughter 10 eggs, second of them 30 eggs and third daughter 50 eggs.

Then she said to them:

"First all of you agree upon price for which you will make sell and stick to that price no matter what. But I hope that mine oldest and most brightest daughter will, beside general agreement on price among all of you , succeed in geting as much money for her 10 eggs as her second daughter for her 30 eggs and that she will then taught her how to get for her 30 eggs as much money as her third daughter for her 50 eggs. Let all of you three get equal money and let price be equal. Beside that, I would like that all of you sell all of your eggs so that total sum of money be integer number not less then 10 dollars for 10 eggs and for all 90 eggs not less than 90 dollars."

*Try to solve this problem. Don't let that oldest and most brightest daughter be smarter than you!*

after all: scrambled eggs

Hello,

here is my solution:

Each girl asks for 50 $, so the total sum is an integer.

the price per egg asked by the youngest girl (yogi): 1 $, so 10 eggs will cost at least 10 $

the price per egg asked by the middle aged daughter (mad): 5/3 $, so 10 eggs will cost at least more then 10 $

the price per egg asked by the oldest daughter (odd): 5 $, so 10 eggs will cost at least more then10 $. Obviously she sold golden eggs.

Every daughter earned the same amount of money ... and now I'm going to make some scrambled eggs.

Greetings

EB