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Math Help - Number Problem

  1. #1
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    Number Problem

    Hi I Was Wondering How I Would Go About Geting All Possible Combinations For Numbers 1 Through To 8, I Know I Sound Real Dumb But Maths Isn't My Forte, At My School If Someone Gets It They Win $200 ^^

    Any Help Would Be Appreciated
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  2. #2
    Super Member malaygoel's Avatar
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    Smile

    Quote Originally Posted by Maths Illiterate
    Hi I Was Wondering How I Would Go About Geting All Possible Combinations For Numbers 1 Through To 8, I Know I Sound Real Dumb But Maths Isn't My Forte, At My School If Someone Gets It They Win $200 ^^

    Any Help Would Be Appreciated
    Can you give an example of what kind of combination you are talking about?
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  3. #3
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    11111111
    11111112
    11111113

    ......
    88888886
    88888887
    88888888

    That Kind Of Thing
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  4. #4
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    Quote Originally Posted by Maths Illiterate
    11111111
    11111112
    11111113

    ......
    88888886
    88888887
    88888888

    That Kind Of Thing
    Simple.

    For each slot you have eight possibilities.
    And there are eight slots thus you have.
    8^8=16777216.

    I really do not see what is so challenging about this problem that the schools would offer $200 dollars for anyone who can answer it (in fact the school can reject this deal because in law a contract is valid when there is consideration-meaning both parties gain something, which is not true here, thus no contract-basically no $200). Unless it is a special-ed school
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  5. #5
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    Shouldn't the answer be 8^8 divided by 8 factorial?
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  6. #6
    Super Member malaygoel's Avatar
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    Quote Originally Posted by beens_angie
    Shouldn't the answer be 8^8 divided by 8 factorial?
    No, because arrangement does matter here.You can see it in the third post of this thread.

    KeepSmiling
    Malay
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  7. #7
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    In the third thread I understand that different combinations are given. It does not verify if different arrangements are counted

    e.g. 11111112 and
    21111111

    So I am asking now,....the question specified "combinations", Shouldn't arrangements be excluded?

    I agree that my calculation to exclude the arrangements was wrong however I don't think it is simply 8^8 if arrangements are not counted.

    waiting for reply
    beens
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