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Thread: square root question.

  1. #1
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    square root question.

    \sqrt{9^{16x^2}}=\begin{cases}\text{a) }3^{4x} &\text{b) } 3^{16x^2}\\\text{c) }9^{4x^2}&\text{d) }9^{8x}\end{cases}
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  2. #2
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    Re: square root question.

    Spoiler:
    I say (b) ...
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  3. #3
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    Re: square root question.

    Quote Originally Posted by skeeter View Post
    Spoiler:
    I say (b) ...
    i agree
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  4. #4
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    Re: square root question.

    \sqrt{9^{16x^2}} \ = \ \sqrt{(3^2)^{16x^2}} \ = \ \sqrt{3^{[2(16x^2)]}} \ = \  \sqrt{(3^{16x^2})^2} \ =  \ 3^{16x^2}  **





    ** \sqrt{A^2} \ = \ |A|,  but the expression for A here is always non-negative, so the final expression in the above line follows.
    Last edited by greg1313; Feb 7th 2017 at 11:19 AM.
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  5. #5
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    Re: square root question.

    agree with you
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  6. #6
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    Re: square root question.

    I almost was fooled by (d)! (b) 3^{16x^2} is equivalent to 9^{8x^2} but (d), of course, does not have x squared.
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  7. #7
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    Re: square root question.

    Next, we can do some superroot problems! Inverse tetration is a hoot!
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