We define the sequence: Prove that: A nice identity indeed , it turned out to be a bit of a surprise really Go ahead, it's your turn to prove it
Follow Math Help Forum on Facebook and Google+
Let We have so and , Now we can show the result by induction: and Assume that
a result of this problem is this identity: because: where and
I prefer to use this complicated ( depends on you ) method and consider and is the differential operator sum of them : multiply compare the coefficient of from the left hand side : we obtain the series from your question from the right hand side :
View Tag Cloud