At a party, everyone shook hands with everybody else.
There were 66 handshakes. How many people were at the
basic drawn out method
Triangle numbers . . .
1 person shake hands 0 times (set n=0 as 1 person cannot create a handshake)
2 people shake hands 1 time set n=1
3 people shake hands 3 times set n=2
4 people shake hands 6 times set n=3 etc
n(n+1) = 66
n(n+1) = 132
therefore you want two numbers with a difference of 1 that multiply together to give you 132.
11x12=132 therefore n=11
A slightly different way of looking at it: each of the n people shakes hands with each of the n- 1 hand shakes. So n people have n(n- 1) hand shakes. But each hand shake involves 2 people so the actual number of hand shakes is n(n- 1)/2. Solve n(n-1)/2= 66