Results 1 to 6 of 6

Thread: [SOLVED] and now something easy

  1. #1
    xanblade
    Guest

    [SOLVED] and now something easy

    12345678
    1 Ioswwath
    2 Camolvdl
    3 Gingxnsy
    4 Pauoseue
    5 Rwievdba
    6 Kayassoz
    7 Sbczyeaz
    8 Zakgvrka


    Clue

    . 1 2 3 4 5 6 7 8
    1. 12-14-13-8-6-15-13-10
    2. 11- 9- 8- 8-11-7-14-15
    3. 9-12-13-14-9-13-16-10
    4. 9- 7-10-12-11-12-10-11
    5. 8- 6- 7- 8- 9- 5- 3- 7
    6. 6-10-8-10-5-11- 4- 6
    7. 10-9-11-7- 5- 9- 7- 5
    8. 4-2-12- 8- 6- 4- 9- 3
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor Quick's Avatar
    Joined
    May 2006
    From
    New England
    Posts
    1,024
    does anyone know what xanblade is talking about?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    5
    Quote Originally Posted by Quick
    does anyone know what xanblade is talking about?
    No but I expect its connected with an online game.

    RonL
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    11,158
    Thanks
    734
    Awards
    1
    Quote Originally Posted by CaptainBlack
    No but I expect its connected with an online game.

    RonL
    Or some kind of cryptogram?

    -Dan
    Follow Math Help Forum on Facebook and Google+

  5. #5
    MHF Contributor Quick's Avatar
    Joined
    May 2006
    From
    New England
    Posts
    1,024

    an important point

    It seems to me that the fact that there are 8 letters to every word and 8 numbers for every clue is an important thing to know.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
    Posts
    12,028
    Thanks
    849
    Some alignment may help . . .
    Code:
      1 2 3 4 5 6 7 8 
    1 I O S W W A T H 
    2 C A M O L V D L 
    3 G I N G X N S Y
    4 P A U O S E U E 
    5 R W I E V D B A 
    6 K A Y A S S O Z 
    7 S B C Z Y E A Z 
    8 Z A K G V R K A 
    
    
    Clue
    
        1  2  3  4  5  6  7  8 
    1  12 14 13  8  6 15 13 10 
    2  11  9  8  8 11  7 14 15 
    3   9 12 13 14  9 13 16 10
    4   9  7 10 12 11 12 10 11
    5   8  6  7  8  9  5  3  7
    6   6 10  8 10  5 11  4  6
    7  10  9 11  7  5  9  7  5
    8   4  2 12  8  6  4  9  3
    . . . . . or not.


    I have a theory . . .

    Think of the first chart as an "addition table".

    We have: $\displaystyle 1 + 1 \,= \,2 \;\Rightarrow\; I$

    Then: $\displaystyle 1 + 2 \,= \,2 + 1 \,= \,3 \;\Rightarrow\; O,\;C$

    And: $\displaystyle 1 + 3 \,= \,2 + 2\,=\,3 + 1\,=\,4\:\Rightarrow\;S,\;A,\:G$

    . . and so on.


    In the "Clue" chart, we can replace the "2" with $\displaystyle I.$

    We can replace the two occurances of "3" with either $\displaystyle O$ or $\displaystyle C.$

    We can replace the three occurances of "4" with $\displaystyle S,\;A,\;G.$


    I've counted the numbers in Clue and they "fit".

    . $\displaystyle 2 \Rightarrow I$
    . $\displaystyle 3 \Rightarrow O,\;C$
    . $\displaystyle 4 \Rightarrow S,\;A,\;G$
    . $\displaystyle 5 \Rightarrow W,\;M,\;I,\;P$
    . $\displaystyle 6 \Rightarrow W,\;O,\;N,\,A,\;R$
    . $\displaystyle 7 \Rightarrow A,\;L,\;G,\;U,\;W,\;K$
    . $\displaystyle 8 \Rightarrow T,\;V,\,X,\,O,\;I,\,A,\;S$
    . $\displaystyle 9 \Rightarrow H,\;D,\;N,\;S,\;E,\;Y,\;B,\;Z$
    $\displaystyle 10 \Rightarrow L,\;S,\;E,\;V,\;A,\;C,\;A$
    $\displaystyle 11 \Rightarrow Y,\,U,\,D,\;S,\;Z,\;K$
    $\displaystyle 12 \Rightarrow E,\;B,\;S,\;Y,\;G$
    $\displaystyle 13 \Rightarrow A,\;O,\;E,\,V$
    $\displaystyle 14 \Rightarrow Z,\;A,\;R$
    $\displaystyle 15 \Rightarrow Z,\;K$
    $\displaystyle 16 \Rightarrow A$


    I would guess that, if we place the correct letters into the Clue chart,
    . . we will get eight 8-letter words.

    But I've been known to be egregiously wrong . . .
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Cardinality (easy)
    Posted in the Math Challenge Problems Forum
    Replies: 4
    Last Post: Apr 19th 2010, 03:04 PM
  2. [SOLVED] Easy Sig fig question
    Posted in the Math Topics Forum
    Replies: 4
    Last Post: Jan 31st 2010, 05:36 PM
  3. [SOLVED] Easy Integration by Substitution
    Posted in the Calculus Forum
    Replies: 0
    Last Post: Apr 13th 2009, 04:11 PM
  4. [SOLVED] Easy trignoometry question
    Posted in the Trigonometry Forum
    Replies: 4
    Last Post: Jan 30th 2009, 02:24 PM
  5. [SOLVED] Help with an easy proof
    Posted in the Number Theory Forum
    Replies: 1
    Last Post: Jan 7th 2009, 06:59 PM

Search Tags


/mathhelpforum @mathhelpforum