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Math Help - it is really imp plz solve

  1. #1
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    it is really imp plz solve

    A+B+C+D=D+E+F+G=G+H+I=17 where each letter represent a number from 1 to 9. Find
    out what does letter D and G represent if letter A=4
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  2. #2
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    Quote Originally Posted by bharathlece
    A+B+C+D=D+E+F+G=G+H+I=17 where each letter represent a number from 1 to 9. Find
    out what does letter D and G represent if letter A=4
    Let me just answer the title.

    No, it is not impossible to solve. But the solution reqiures too much trial and error, too much reliance on chance. A computer can easily get the answer, but a person,....

    Also, the puzzle is like the game of sudoku. I hate sudoku. Too much trial and error.
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  3. #3
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    hey , man this is the most common asked question in indian puzzle talent show dnt say that u hate some or u like some . give me replay if u got the answer dnt give me some other xyz replay about which u like and which u dnt like . dnt waste ur time by giving replay nor dnt waste my time in reading them. if it hurt u u deserves it coz ur giving replay like dat to me
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  4. #4
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    Quote Originally Posted by bharathlece
    hey , man this is the most common asked question in indian puzzle talent show dnt say that u hate some or u like some . give me replay if u got the answer dnt give me some other xyz replay about which u like and which u dnt like . dnt waste ur time by giving replay nor dnt waste my time in reading them. if it hurt u u deserves it coz ur giving replay like dat to me
    Umm, okay, so you have no sense of humor. I can play that.

    If that is common in your place, how come you cannot solve it?

    I never was hurt. I was just teasing you.

    And I hate sudoku.

    And you have to waste your time reading this.

    And your English is worse than mine.

    (Moderators, I know you have senses of humor.)
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  5. #5
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    Quote Originally Posted by bharathlece
    A+B+C+D=D+E+F+G=G+H+I=17 where each letter represent a number from 1 to 9. Find
    out what does letter D and G represent if letter A=4
    The solution is impossible to get, since you have,
    A+B+C+D=17
    D+E+F+G=17
    G+H+I=17
    Add the equations to get,
    A+B+C+D+E+F+G+H+I+(D+G)=51
    But these letters are the numbers 1,2,...,9 in some order thus,
    (1+2+3...+9)+(G+H)=51
    Thus,
    G+H=6
    Then in the third equation we have that I=11 which is a violation because it cannot be more then 9.
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  6. #6
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    Quote Originally Posted by ThePerfectHacker
    The solution is impossible to get, since you have,
    A+B+C+D=17
    D+E+F+G=17
    G+H+I=17
    Add the equations to get,
    A+B+C+D+E+F+G+H+I+(D+G)=51
    But these letters are the numbers 1,2,...,9 in some order thus,
    (1+2+3...+9)+(G+H)=51
    Thus,
    G+H=6
    Then in the third equation we have that I=11 which is a violation because it cannot be more then 9.
    Perhaps the A, B, ..., I aren't all distinct? He didn't actually say that they were, but that was my first inclination as well.

    Still, we have 4 conditions on 9 variables (counting the condition that all A, B,..., I are between 0 and 10 as a condition). I don't see how to solve it uniquely.

    -Dan
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  7. #7
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    Quote Originally Posted by topsquark
    Perhaps the A, B, ..., I aren't all distinct? He didn't actually say that they were, but that was my first inclination as well.

    Still, we have 4 conditions on 9 variables (counting the condition that all A, B,..., I are between 0 and 10 as a condition). I don't see how to solve it uniquely.

    -Dan
    Linear Algebra does not work here. Because we assume the elements are in some field. The integers do not form a field. Thus, the fact that there are 3 equations and 9 variables does not mean we cannot have a unique solution.
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  8. #8
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    Further, they if they are not distinct then it solves easily for example,
    A=4
    B=1
    C=3
    D=9
    E=1
    F=1
    G=6
    H=2
    I=9
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