solve (3?3)?3?3?3=29 using + x / - only once. please help. thanks

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- Oct 10th 2007, 11:49 PMgu12lsfive 3s math puzzle please help
solve (3?3)?3?3?3=29 using + x / - only once. please help. thanks

- Oct 11th 2007, 01:38 AMtukeywilliams
You know the cant go in the last position because 29 is prime.

- Nov 18th 2007, 06:04 AMVariant
x must be a variable it seems, if there is going to be a solution.

(3-3) = 0, you'll get nowhere with that.

(3/3) = 1, can't get very far with a 1 either.

(3x3) = 9, you used your multiply, you have one add to use and it's downhill from there.

(3+3) = 6, used your add already, 3 x 6 = 18, downhill from there.

I found it:

(3 + 3)x3 - 3 / 3 = 29, where x = 5

6*5*3 = 90

90 - 3 = 87

87 / 3 = 29

I found it by figuring 29*3 = 87, so I must have 87 / 3 at the end... it wasn't a very good way of doing it though.

Also, if you think there's away of doing it with x being a multiply symbol, go ahead and try... but I guarantee you it's a waste of time.

Nevermind, this is apparently wrong due to order of operations.

Someone on another forum found answers. One is:

x =3

(3x3) + 3 - 3/3 = 29

Apparently there are others also.