Thread: Sum=0

Find values of natural numbers n, 0<n<100 for which appropriate selection of +/- signs makes the following equality true:

I'll start this thing: n = 20
cubes of(1,2,5,6,16,17,18,19) = 22050 ; sum cubes (n=20) = 44100

Sum of n cubes must be even, of course.
So these n's are possibles:
3,4 : 7,8 : 11,12 : ......... : 95,96 : 99,100
Kick these out:
1,2 : 5,6 : 9,10 : ...........: 93,94 : 97,98

Your turn, Plato