Results 1 to 8 of 8

Math Help - Need a solution to a number problem.

  1. #1
    Newbie
    Joined
    Jul 2012
    From
    Australia
    Posts
    5

    Need a solution to a number problem.

    Hi All,
    Not sure I am in the right place.
    The problem I have is that I need to group numbers 1 through 24 into 12 groups of 4 then change each combination of 4 numbers so as they do not meet each other again.
    As an example once 1,2,3 & 4 have been grouped together they can then not appear together again in the same group.

    Any help or solution suggestions would be appreciated.

    Rob
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor

    Joined
    Aug 2006
    Posts
    18,615
    Thanks
    1582
    Awards
    1

    Re: Need a solution to a number problem.

    Quote Originally Posted by bowlrig View Post
    Hi All,
    Not sure I am in the right place.
    The problem I have is that I need to group numbers 1 through 24 into 12 groups of 4 then change each combination of 4 numbers so as they do not meet each other again.
    As an example once 1,2,3 & 4 have been grouped together they can then not appear together again in the same group.
    It is impossible to "group numbers 1 through 24 into 12 groups of 4" unless some numbers appear in more than one group. Is that what you mean? If so, how do you rearrange the groups?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Jul 2012
    From
    Australia
    Posts
    5

    Re: Need a solution to a number problem.

    Sorry, I should have re-read before I posted.
    It should read "group numbers 1 through 24 into 6 groups of 4"

    Rob
    Last edited by bowlrig; July 30th 2012 at 04:37 PM. Reason: Spelling
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Newbie
    Joined
    Jul 2012
    From
    Australia
    Posts
    5

    Re: Need a solution to a number problem.

    Can anyone recommend someone on here to help me solve this?

    Rob
    Follow Math Help Forum on Facebook and Google+

  5. #5
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    11,629
    Thanks
    430

    Re: Need a solution to a number problem.

    Quote Originally Posted by bowlrig View Post
    Sorry, I should have re-read before I posted.
    It should read "group numbers 1 through 24 into 6 groups of 4"
    The problem I have is that I need to group numbers 1 through 24 into 6 groups of 4 then change each combination of 4 numbers so as they do not meet each other again.
    As an example once 1,2,3 & 4 have been grouped together they can then not appear together again in the same group.
    6 groups of 4 ...

    1, 2, 3, 4

    5, 6, 7, 8

    9, 10, 11, 12

    and so on ...


    then, so they don't meet again ...

    1, 5, 9, 13

    2, 6, 10, 14

    3, 7, 11, 15

    and so on ...
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Newbie
    Joined
    Jul 2012
    From
    Australia
    Posts
    5

    Re: Need a solution to a number problem.

    Hi Skeeter,
    That is the concept but I am trying to get all numbers to be together at least once.
    Follow Math Help Forum on Facebook and Google+

  7. #7
    MHF Contributor
    Joined
    Dec 2007
    From
    Ottawa, Canada
    Posts
    3,102
    Thanks
    68

    Re: Need a solution to a number problem.

    Hard to know what you mean...
    What do you expect to see using 1 to 9, 3 groups of 3?
    List them; shouldn't be too many...
    Follow Math Help Forum on Facebook and Google+

  8. #8
    Newbie
    Joined
    Nov 2012
    From
    Southern California
    Posts
    18
    Thanks
    1

    Re: Need a solution to a number problem.

    Quote Originally Posted by bowlrig View Post
    That is the concept but I am trying to get all numbers to be together at least once.
    Put another way, you have 24 people and 6 cars. Each day, the people pick a car to ride in that day.
    This repeats as long as possible (a week, for example) such that no 2 people share a car on 2 different days.

    Is this the kind of problem you are trying to solve?

    Just one observation.
    Person number 1 has 23 different people he could potentially share a car with. Each day, he shares a car with three (four people per car).
    Since 23 is not divisible by 3, he can't share a car with everyone else exactly once.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. number of solution of x*x =1 (mod n) ??
    Posted in the Number Theory Forum
    Replies: 7
    Last Post: May 5th 2013, 04:33 AM
  2. number of solution
    Posted in the Calculus Forum
    Replies: 1
    Last Post: June 2nd 2011, 09:52 AM
  3. number of solution
    Posted in the Calculus Forum
    Replies: 0
    Last Post: January 3rd 2011, 12:56 AM
  4. number/solution problem
    Posted in the Algebra Forum
    Replies: 4
    Last Post: August 18th 2008, 09:25 AM
  5. Complex number solution for theta
    Posted in the Pre-Calculus Forum
    Replies: 4
    Last Post: June 6th 2008, 08:45 AM

Search Tags


/mathhelpforum @mathhelpforum