# Need a solution to a number problem.

• Jul 30th 2012, 04:05 AM
bowlrig
Need a solution to a number problem.
Hi All,
Not sure I am in the right place.
The problem I have is that I need to group numbers 1 through 24 into 12 groups of 4 then change each combination of 4 numbers so as they do not meet each other again.
As an example once 1,2,3 & 4 have been grouped together they can then not appear together again in the same group.

Any help or solution suggestions would be appreciated.

Rob
• Jul 30th 2012, 04:47 PM
Plato
Re: Need a solution to a number problem.
Quote:

Originally Posted by bowlrig
Hi All,
Not sure I am in the right place.
The problem I have is that I need to group numbers 1 through 24 into 12 groups of 4 then change each combination of 4 numbers so as they do not meet each other again.
As an example once 1,2,3 & 4 have been grouped together they can then not appear together again in the same group.

It is impossible to "group numbers 1 through 24 into 12 groups of 4" unless some numbers appear in more than one group. Is that what you mean? If so, how do you rearrange the groups?
• Jul 30th 2012, 05:31 PM
bowlrig
Re: Need a solution to a number problem.
Sorry, I should have re-read before I posted.
It should read "group numbers 1 through 24 into 6 groups of 4"

Rob
• Jul 31st 2012, 06:51 PM
bowlrig
Re: Need a solution to a number problem.
Can anyone recommend someone on here to help me solve this?

Rob
• Jul 31st 2012, 07:51 PM
skeeter
Re: Need a solution to a number problem.
Quote:

Originally Posted by bowlrig
Sorry, I should have re-read before I posted.
It should read "group numbers 1 through 24 into 6 groups of 4"

Quote:

The problem I have is that I need to group numbers 1 through 24 into 6 groups of 4 then change each combination of 4 numbers so as they do not meet each other again.
As an example once 1,2,3 & 4 have been grouped together they can then not appear together again in the same group.
6 groups of 4 ...

1, 2, 3, 4

5, 6, 7, 8

9, 10, 11, 12

and so on ...

then, so they don't meet again ...

1, 5, 9, 13

2, 6, 10, 14

3, 7, 11, 15

and so on ...
• Jul 31st 2012, 08:27 PM
bowlrig
Re: Need a solution to a number problem.
Hi Skeeter,
That is the concept but I am trying to get all numbers to be together at least once.
• Aug 3rd 2012, 05:09 PM
Wilmer
Re: Need a solution to a number problem.
Hard to know what you mean...
What do you expect to see using 1 to 9, 3 groups of 3?
List them; shouldn't be too many...
• Nov 27th 2012, 12:10 PM
Re: Need a solution to a number problem.
Quote:

Originally Posted by bowlrig
That is the concept but I am trying to get all numbers to be together at least once.

Put another way, you have 24 people and 6 cars. Each day, the people pick a car to ride in that day.
This repeats as long as possible (a week, for example) such that no 2 people share a car on 2 different days.

Is this the kind of problem you are trying to solve?

Just one observation.
Person number 1 has 23 different people he could potentially share a car with. Each day, he shares a car with three (four people per car).
Since 23 is not divisible by 3, he can't share a car with everyone else exactly once.