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The goal is to make a schedule that will allow 8 teams to play each of 4 games once without playing the same team twice.
For instance,
Games 1 Game 2 Game 3 Game 4 Week 1 1 vs 8 2 vs 7 3 vs 6 4 vs 5 Week 2 Week 3 Week 4
In week 2, each team must play a different game without ever playing a team that they have previously face.
1-2, 3-4, 5-6, 7-8
1-3, 2-4, 5-7, 6-8
1-4, 2-3, 5-8, 6-7
1-5, 2-6, 3-7, 4-8
Check:
1: 2,3,4,5
2: 1,3,4,6
3: 1,2,4,7
4: 1,2,3,8
5: 1,6,7,8
6: 2,5,7,8
7: 3,5,6,8
8: 4,5,6,7
I do not understand your answer. Is it in the same format as my table? If so, teams are playing the same game twiceQuote:
Originally Posted by Wilmer
Well then, what does this mean: "play each of 4 games once"?Quote:
Originally Posted by ben61693
EDIT:
ok ok ! Think I see what you mean:
in your example, team1 cannot play team8 again, PLUS both teams cannot appear under Game1 again; yes?
Tried a bit: can only come close (Crying)
I'll keep trying...YOU try too (Wink)
Here you go:
No charge (Wink)Code:G1 G2 G3 G4
W1 12 34 56 78
W2 35 17 28 46
W3 48 26 37 15
W4 67 58 14 23
Quote:
Originally Posted by ben61693
Thank you so much. I kept getting 3vs5 twice for some reason. Just out of curiosity. How did you do it? Pure guessing or some strategy involved?Quote:
Originally Posted by Wilmer
Wrote short computer program to do about half a case; trial and error for other half.
Here's another solution:
Code:G1 G2 G3 G4
W1 17 45 28 36
W2 26 38 15 47
W3 35 27 46 18
W4 48 16 37 25
By the way, your problem really is:
You have 28 2digit numbers:
12,13,14,15,16,17,18,23,24,25,26,27,28,34,35,36,37 ,38,45,46,47,48,56,57,58,67,68,78
Enter 16 of these numbers in a 4 by 4 array such that:
1: the 4 numbers in each row are made up of all digits 1 to 8
2: the 4 numbers in each column are made up of all digits 1 to 8
This makes it relatively easy to write a computer program.