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- October 16th 2011, 10:49 AMRandom Variablemore integrals
Don't hide solutions.

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2)

3) - October 16th 2011, 12:34 PMRandom VariableRe: more integrals
Please don't give hints.

- October 17th 2011, 03:36 PMuniquesailorRe: more integrals
- October 17th 2011, 11:46 PMFernandoRevillaRe: more integrals
We have , so the following function is well defined (by means of a convergent integral):

Then

Using the substitution :

Using the substitution :

Integrating both sides:

For we have that is, . Then, .

As a consequence:

- December 5th 2011, 12:10 AMsimplependulumRe: more integrals
Consider , we have

so the answer is - March 4th 2012, 11:19 PMsbhatnagarRe: more integrals