# Solve the logarithmic equation

• Jun 10th 2011, 02:25 PM
DeMath
Solve the logarithmic equation
Solve analytically the logarithmic equation

$\log_{x+1}(\sqrt{2}-1)\cdot\log_{4-2\sqrt{2}}(x^2+2x+2)=1$
• Jun 11th 2011, 01:40 AM
Unbeatable0
Let $a=\sqrt{2}-1$ and $b=x+1$. Then the equation becomes:

$\displaystyle{\frac{\ln{a}}{\ln{b}}\cdot \frac{\ln(b^2+1)}{\ln(a^2+1)}}=1$

or equivalently:

$\displaystyle{\frac{\ln{a}}{\ln(a^2+1)}=\frac{\ln b}{\ln(b^2+1)}}$

Now, the derivative of $\frac{\ln{t}}{\ln(t^2+1)}$ is

$\frac{\frac{\ln(t^2+1)}{t}-\frac{2t\ln t}{t^2+1}}{\ln^2(t^2+1)} = \frac{(t^2+1)\ln(t^2+1)-t^2\ln t^2}{t(t^2+1)\ln^2(t^2+1)} > 0$

So we conclude that the only solution is $a=b$, or:

$x=\sqrt{2}-2$