Originally Posted by yiyayiyayo
The Least Significant Digit (LSD) of x^N is 1, and the LSD of y^N is 6,
so the LSD of x^N+y^N is 7 which is not the LSD of z^N which is 5.
A computer scientist claims that he proved somehow that the Fermat theorem is correct for the following 3 numbers:
He announces these 3 numbers and calls for a press conference where he is going to present the value of N (to show that
x^N + y^N = z^N
and that the guy from Princeton was wrong). As the press conference starts, a 10-years old boy raises his hand and says that the respectable scientist has made a mistake and the Fermat theorem cannot hold for those 3 numbers. The scientist checks his computer calculations and finds a bug.
How did the boy figure out that the scientist was wrong?
The 10-year old boy knows how to add.Originally Posted by yiyayiyayo
The last digit of x is 6.
6^N will have 6 as the last digit.
The y has 1 at the end, and 1^N will give 1 always.
The z has has 5 at the end, and 5^N will give 5 at the end too.
The young lad added 6+1 and he was getting 7, not 5.
Yeah. Steroids, steroids for this finger.
Also, I just cannot get off the "mana" re all new news/articles about my Pittsburgh Steelers! It's been a long time coming. I will not miss them for any Math forum. I am not from the 'Burgh but I am a member of the Steelers Nation since 1974! Isn't nice to have Internet?! Instant news, pictures, voice broadcast, ....
If ThePerfectHacker would delete this, I would sue him in court. Yeah.
I don't want to comment on anybody's answer, but since this answer is yours (get the hint?), I will break my policy on this.Originally Posted by ThePerfectHacker
The question mentioned Fermat (you have a poll on greatest mathemations and you don't recognize Fermat's Last Theorem?) so the N here is greater than 2. So even if the lad added successfuly the given X,Y,Z, your answer is wrong because that would have been for N=1.
Been from short vacation, didn't go to work now so can answer here now in this time-window.
Hello i have a simple way to do that:Originally Posted by yiyayiyayo
we have got x+y>z
so x^n +y^n = ((x+y)^n)-K(see above) >z^n for a->a^n is a strictly growing up function!
K is the positive integer for wich x^n+K+y^n =(x+y)^n (you know the formula to get K) don't you!
(qued) this demonstration is stupid i should'nt have drink a little sup of paddy before lurking that site but they are indeed so much reason for numbers not to satisfy the "equation" that's its a shame nobody (except anybody) can give a simple solution to this "riddle"