I have a solution using contour integration. You could either try to replicate that solution, or preferably find a simpler approach.

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- February 14th 2011, 05:59 PMRandom Variabledefinite integral #4

I have a solution using contour integration. You could either try to replicate that solution, or preferably find a simpler approach.

__Spoiler__: - February 14th 2011, 09:24 PMKrizalid
Integrate by parts and the integral equals now use and that gives the answer

- February 15th 2011, 09:53 AMRandom Variable
- February 15th 2011, 10:27 AMKrizalid

now put and get

- February 15th 2011, 02:46 PMtopsquark
- February 15th 2011, 02:52 PMKrizalid
You mean power series for contangent? I don't know it.

Perhaps it's better you to share your solution. :D - February 15th 2011, 03:39 PMtopsquark
- February 15th 2011, 09:03 PMCaptainBlack
It lurks about halfway down >>this<< page.

CB - February 18th 2011, 06:18 PMchiph588@