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Math Help - Any other solution to this inequality ?

  1. #1
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    Any other solution to this inequality ?

    Hi everyone !
    I found that inequality that i proved , but i wanted another solution .
    Show that for all a,b and c positive real numbers , the following inequality holds:

    And please , don't tell me it is pre-calculus !

    Anybody with another solution ?
    (if you need mine , say it )


    Moderator edit: Moved from Pre-algebra and Algebra. Closed until OP reads and follows the subforum rules for posting here.
    Last edited by mr fantastic; January 14th 2011 at 01:19 PM. Reason: Moved, merged threads.
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  2. #2
    Member Pranas's Avatar
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    Maybe it's a matter of notation in different regions, bet personally I am not exactly sure of summation
    \displaystyle \[\sum\limits_{cyc} {} \]
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  3. #3
    MHF Contributor Also sprach Zarathustra's Avatar
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    Quote Originally Posted by Pranas View Post
    Maybe it's a matter of notation in different regions, bet personally I am not exactly sure of summation
    \displaystyle \[\sum\limits_{cyc} {} \]
    cyc=cyclic
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  4. #4
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    Can i give a hint ?
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  5. #5
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    I still don't understand what \displaystyle\sum_{cyc}\frac{a}{(b+c)^2} is. Is it \displaystyle\frac{a}{(b+c)^2}+\frac{b}{(a+c)^2}+\  frac{c}{(a+b)^2}?
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  6. #6
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    Yes it is !
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  7. #7
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    Well , you must use both Cauchy-Schwartz and Nesbitt inequalities .
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