# Any other solution to this inequality ?

• January 14th 2011, 05:22 AM
Any other solution to this inequality ?
Hi everyone !
I found that inequality that i proved , but i wanted another solution .
Show that for all a,b and c positive real numbers , the following inequality holds:
http://latex.codecogs.com/gif.latex?...c{9}{4(a+b+c)}
And please , don't tell me it is pre-calculus ! (Giggle)

Anybody with another solution ?
(if you need mine , say it :D )

Moderator edit: Moved from Pre-algebra and Algebra. Closed until OP reads and follows the subforum rules for posting here.
• January 14th 2011, 07:08 AM
Pranas
Maybe it's a matter of notation in different regions, bet personally I am not exactly sure of summation
$\displaystyle $\sum\limits_{cyc} {}$$
• January 14th 2011, 07:18 AM
Also sprach Zarathustra
Quote:

Originally Posted by Pranas
Maybe it's a matter of notation in different regions, bet personally I am not exactly sure of summation
$\displaystyle $\sum\limits_{cyc} {}$$

cyc=cyclic
• January 14th 2011, 07:20 AM
I still don't understand what $\displaystyle\sum_{cyc}\frac{a}{(b+c)^2}$ is. Is it $\displaystyle\frac{a}{(b+c)^2}+\frac{b}{(a+c)^2}+\ frac{c}{(a+b)^2}$?