Here's a different example of what I'm talking about, but this time I'll do it with a square.
Say you're checking the number 9 to see if the sum of the digits to its square is also 9. So 9^2 = 81 and 8 + 1 = 9 which is what you started off with so 9 does fulfill the conditions of the problem (when you're considering squares). Now instead of squares, check the cubes of numbers, sum their digits and see if you can get the original number back that you just cubed.
If you can, then you've found one the six answers to the problem.
Go get 'em Tonio, I know you can do it.