Given and , show .

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- Aug 17th 2010, 09:41 PMchiph588@Riemann Zeta Function
Given and , show .

- Aug 18th 2010, 11:30 AMVlasev
Chiph, I believe that the series should be:

Here is my solution:

__Spoiler__: - Aug 21st 2010, 04:07 AMVlasev
Where did you find this identity?

- Aug 22nd 2010, 08:42 PMchiph588@
- Aug 22nd 2010, 09:53 PMVlasev
There is one online but it's just a special case of this one. It's for x = 1. They do reference the paper where it was derived and I'm sure they did it for arbitrary x. Maybe that's what you saw. Thanks though.

I think the series could be derived with a straight application of Euler summation: Euler summation - Wikipedia, the free encyclopedia