Solve the functional equation: , where . P.S. Good luck!
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it seems that are all the solutions ...
let b=beta taking the logarithm of the both sides , we get : , let we get : dividing both sides by : let : we have : which is equivalent to : , if i remember well , the solution of the Last equation is for some real a , a difficult result of Erdos !!
you'd need some sort of continuity condition i guess. anyway, just put to end up with the simple equation
Originally Posted by NonCommAlg it seems that are all the solutions ... Yes, but it would be even more interesting see your full solution, dear NonCommAlg.
Originally Posted by DeMath Yes, but it would be even more interesting see your full solution, dear NonCommAlg. i've already posted it. see my second response.
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