Nothing, the owner has $27 (that is $25+$2) and each of the guys has $1 - total $30.Originally Posted by amberbrown
I need help with this one ASAP:
3 guys decide to rent a room while traveling. They are told the room is $30, so they equally divide the room to be $10 per guy. In the course of registration, the manager says they are offering a discount, the room will be $25. To aid them in splitting the difference, the owner said I will keep $2 and you will each get $1 back. That would make their share $9 per guy. $9 x 3 = $27. If the owner kept $2, what happened to the other dollar??????
$9, they initially paid $10 and received $1 back, 3x9=27.Originally Posted by amberbrown
The $2 is what the owner kept over the $25 he was entitled to
not the difference between what the guys finally paid and what
they initially paid.
There is no other dollar. The riddle is all about misdirection. It mentionsOriginally Posted by amberbrown
the $27 and the $2 and implies that these should sum to $30. But they
should not be added they are not what you think. The $2 is how much
more than the owner is entitled to that he keeps, so he keeps $27,
but the problem is trying to suggest that $30 should equal what the
guys have paid plus the the extra that the owner keeps, but it ain't so.
Of the $30
owner got $27
renter #1 got $1
renter #2 got $1
renter #3 got $1
total = $30
The question is misleading, they are mixing up two different things, how much extra the owner took and how much the guys paid, the question is a mess but the answer is clear.