# Math Help - I have a challange

1. ## I have a challange

as the title sez i have a challange, altho for some of you won't be really a challange, more like a walk in the park type of thing, here it goes:

there are 3(a,b,c) numbers and each number has 3 values(d,e,f) as follows:

a: d=150,e=0,f=255
b: d=255,e=150,f=0
c: d=0,e=255,f=150

those are the numbers and they're values, u have to add the numbers according to the following ecuasion:

0.9*x + 0.1*y = z

where x is the main number that u can chose freely between the 3 numbers above, and y is the second number, chose freely again between the 3 numbers above.
So to each one of the 3 values of the number the ecuation is applyed individual

after that Z will become the main number and u'll be able to chose freely on the Y number from the 3 numbers mentioned above, continueing with the ecuation until the 3 values of Z will be these: d=148,e=156,f=137

I'll make an example

0.9*a + 0.1*c = d where d has the next values: d=135,e=25.5,f=244.5

0.9*d + 0.1*a =f where f has the next values: d=136.5,e=22.95,f=243

0.9*f + 0.1*b = g where g has the next values d=145.35,e=35.655,f=218.7

and so on

have fun

don't forget, the final number msut have these values : d=148,e=156,f=137

2. Originally Posted by NightM4k3r
as the title sez i have a challange, altho for some of you won't be really a challange, more like a walk in the park type of thing, here it goes:

there are 3(a,b,c) numbers and each number has 3 values(d,e,f) as follows:

a: d=150,e=0,f=255
b: d=255,e=150,f=0
c: d=0,e=255,f=150

those are the numbers and they're values, u have to add the numbers according to the following ecuasion:

0.9*x + 0.1*y = z

where x is the main number that u can chose freely between the 3 numbers above, and y is the second number, chose freely again between the 3 numbers above.
So to each one of the 3 values of the number the ecuation is applyed individual

after that Z will become the main number and u'll be able to chose freely on the Y number from the 3 numbers mentioned above, continueing with the ecuation until the 3 values of Z will be these: d=148,e=156,f=137

I'll make an example

0.9*a + 0.1*c = d where d has the next values: d=135,e=25.5,f=244.5

0.9*d + 0.1*a =f where f has the next values: d=136.5,e=22.95,f=243

0.9*f + 0.1*b = g where g has the next values d=145.35,e=35.655,f=218.7

and so on

have fun

don't forget, the final number msut have these values : d=148,e=156,f=137
Hello, NightMaker! You're problem should belong in the puzzle section!

3. Originally Posted by NightM4k3r
as the title sez i have a challange, altho for some of you won't be really a challange, more like a walk in the park type of thing, here it goes:

there are 3(a,b,c) numbers and each number has 3 values(d,e,f) as follows:

a: d=150,e=0,f=255
b: d=255,e=150,f=0
c: d=0,e=255,f=150

those are the numbers and they're values, u have to add the numbers according to the following ecuasion:

0.9*x + 0.1*y = z

where x is the main number that u can chose freely between the 3 numbers above, and y is the second number, chose freely again between the 3 numbers above.
So to each one of the 3 values of the number the ecuation is applyed individual

after that Z will become the main number and u'll be able to chose freely on the Y number from the 3 numbers mentioned above, continueing with the ecuation until the 3 values of Z will be these: d=148,e=156,f=137

I'll make an example

0.9*a + 0.1*c = d where d has the next values: d=135,e=25.5,f=244.5

0.9*d + 0.1*a =f where f has the next values: d=136.5,e=22.95,f=243

0.9*f + 0.1*b = g where g has the next values d=145.35,e=35.655,f=218.7

and so on

have fun

don't forget, the final number msut have these values : d=148,e=156,f=137
Couly you clarify what you are trying to do?

I'm not sure which are variables and which are constants.
It is not clear that the d in one line means the same d as previously defined for a value of d or if d actually is changed simultaneously for all d, when any d is changed.
Is that part of the puzzle?

OR
is this what you intend:

$a_1=150 : a_2=0 : a_3= 255$
$b_1=255 : b_2= 150: b_3= 0$
$c_1= 0 : c_2= 255: c_3= 150$

$d_1= 0.9*a_1 + 0.1*c_1 = 135$
$d_2= 0.9*a_2 + 0.1*c_2 = 25.5$
$d_3= 0.9*a_3 + 0.1*c_3 = 244.5$

[no formula for e]

$f_1= 0.9*d_1 + 0.1*a_1 = 136.5$
$f_2= 0.9*d_2 + 0.1*a_2 = 22.95$
$f_3= 0.9*d_3 + 0.1*a_3 = 243$ How? 245.55 seems possible.

$g_1= 0.9*f_1 + 0.1*b_1 = 145.35$ How? 148.35?
$g_2= 0.9*f_2 + 0.1*b_2 = 35.655$ ok
$g_3= 0.9*f_3 + 0.1*b_3 = 218.7$

is this valid for h?
$h_1= 0.9*a_1 + 0.1*b_1 = 160.50$
$h_2= 0.9*a_2 + 0.1*b_2 = 15.00$
$h_3= 0.9*a_3 + 0.1*b_3 = 229.55$

would this be valid for h?
$h_1= 0.9*a_1 + 0.1*d_1 = 28.50$
$h_2= 0.9*b_2 + 0.1*f_2 = 17.295$
$h_3= 0.9*c_3 + 0.1*g_3 = 36.87$

or this?
$h_1= 0.9*a_1 + 0.1*a_1 = 150.00$
$h_2= 0.9*a_2 + 0.1*a_2 = 0.00$
$h_3= 0.9*a_3 + 0.1*a_3 = 255.00$

or this?
$h_1= 0.9*a_1 + 0.1*b_1 = 160.50$
$h_2= 0.9*a_1 + 0.1*b_1 = 160.50$
$h_3= 0.9*a_1 + 0.1*b_1 = 160.50$

Code:
 u'll be able to chose freely on the Y number from the 3 numbers mentioned above
horizontally 3 numbers or vertically three numbers?

Since you have 150 & 255 & 0 defined in the first column and at some point you want 148 in the first column, then
You will need some combination of r,s,t,u to get the result.

135.5r + 0.15s + 229.5t + 25.5u = 148

r,s,t,u can be positive or negative.