as the title sez i have a challange, altho for some of you won't be really a challange, more like a walk in the park type of thing, here it goes:

there are 3(a,b,c) numbers and each number has 3 values(d,e,f) as follows:

a: d=150,e=0,f=255

b: d=255,e=150,f=0

c: d=0,e=255,f=150

those are the numbers and they're values, u have to add the numbers according to the following ecuasion:

0.9*x + 0.1*y = z

where x is the main number that u can chose freely between the 3 numbers above, and y is the second number, chose freely again between the 3 numbers above.

So to each one of the 3 values of the number the ecuation is applyed individual

after that Z will become the main number and u'll be able to chose freely on the Y number from the 3 numbers mentioned above, continueing with the ecuation until the 3 values of Z will be these: d=148,e=156,f=137

I'll make an example

0.9*a + 0.1*c = d where d has the next values: d=135,e=25.5,f=244.5

0.9*d + 0.1*a =f where f has the next values: d=136.5,e=22.95,f=243

0.9*f + 0.1*b = g where g has the next values d=145.35,e=35.655,f=218.7

and so on

have fun

don't forget, the final number msut have these values : d=148,e=156,f=137