Thread: I have a challange

as the title sez i have a challange, altho for some of you won't be really a challange, more like a walk in the park type of thing, here it goes:

there are 3(a,b,c) numbers and each number has 3 values(d,e,f) as follows:

a: d=150,e=0,f=255
b: d=255,e=150,f=0
c: d=0,e=255,f=150

those are the numbers and they're values, u have to add the numbers according to the following ecuasion:

0.9*x + 0.1*y = z

where x is the main number that u can chose freely between the 3 numbers above, and y is the second number, chose freely again between the 3 numbers above.
So to each one of the 3 values of the number the ecuation is applyed individual

after that Z will become the main number and u'll be able to chose freely on the Y number from the 3 numbers mentioned above, continueing with the ecuation until the 3 values of Z will be these: d=148,e=156,f=137

I'll make an example

0.9*a + 0.1*c = d where d has the next values: d=135,e=25.5,f=244.5

0.9*d + 0.1*a =f where f has the next values: d=136.5,e=22.95,f=243

0.9*f + 0.1*b = g where g has the next values d=145.35,e=35.655,f=218.7

and so on

have fun

don't forget, the final number msut have these values : d=148,e=156,f=137

Originally Posted by NightM4k3r

as the title sez i have a challange, altho for some of you won't be really a challange, more like a walk in the park type of thing, here it goes:

there are 3(a,b,c) numbers and each number has 3 values(d,e,f) as follows:

a: d=150,e=0,f=255
b: d=255,e=150,f=0
c: d=0,e=255,f=150

those are the numbers and they're values, u have to add the numbers according to the following ecuasion:

0.9*x + 0.1*y = z

where x is the main number that u can chose freely between the 3 numbers above, and y is the second number, chose freely again between the 3 numbers above.
So to each one of the 3 values of the number the ecuation is applyed individual

after that Z will become the main number and u'll be able to chose freely on the Y number from the 3 numbers mentioned above, continueing with the ecuation until the 3 values of Z will be these: d=148,e=156,f=137

I'll make an example

0.9*a + 0.1*c = d where d has the next values: d=135,e=25.5,f=244.5

0.9*d + 0.1*a =f where f has the next values: d=136.5,e=22.95,f=243

0.9*f + 0.1*b = g where g has the next values d=145.35,e=35.655,f=218.7

and so on

have fun

don't forget, the final number msut have these values : d=148,e=156,f=137

Hello, NightMaker! You're problem should belong in the puzzle section!

Originally Posted by NightM4k3r

as the title sez i have a challange, altho for some of you won't be really a challange, more like a walk in the park type of thing, here it goes:

there are 3(a,b,c) numbers and each number has 3 values(d,e,f) as follows:

a: d=150,e=0,f=255
b: d=255,e=150,f=0
c: d=0,e=255,f=150

those are the numbers and they're values, u have to add the numbers according to the following ecuasion:

0.9*x + 0.1*y = z

where x is the main number that u can chose freely between the 3 numbers above, and y is the second number, chose freely again between the 3 numbers above.
So to each one of the 3 values of the number the ecuation is applyed individual

after that Z will become the main number and u'll be able to chose freely on the Y number from the 3 numbers mentioned above, continueing with the ecuation until the 3 values of Z will be these: d=148,e=156,f=137

I'll make an example

0.9*a + 0.1*c = d where d has the next values: d=135,e=25.5,f=244.5

0.9*d + 0.1*a =f where f has the next values: d=136.5,e=22.95,f=243

0.9*f + 0.1*b = g where g has the next values d=145.35,e=35.655,f=218.7

and so on

have fun

don't forget, the final number msut have these values : d=148,e=156,f=137

Couly you clarify what you are trying to do?

I'm not sure which are variables and which are constants.
It is not clear that the d in one line means the same d as previously defined for a value of d or if d actually is changed simultaneously for all d, when any d is changed.
Is that part of the puzzle?

OR
is this what you intend:









[no formula for e]



How? 245.55 seems possible.

How? 148.35?
ok


is this valid for h?




would this be valid for h?




or this?




or this?

Code:

 u'll be able to chose freely on the Y number from the 3 numbers mentioned above

horizontally 3 numbers or vertically three numbers?

Since you have 150 & 255 & 0 defined in the first column and at some point you want 148 in the first column, then
You will need some combination of r,s,t,u to get the result.

135.5r + 0.15s + 229.5t + 25.5u = 148

r,s,t,u can be positive or negative.