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Math Help - I have a challange

  1. #1
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    I have a challange

    as the title sez i have a challange, altho for some of you won't be really a challange, more like a walk in the park type of thing, here it goes:

    there are 3(a,b,c) numbers and each number has 3 values(d,e,f) as follows:

    a: d=150,e=0,f=255
    b: d=255,e=150,f=0
    c: d=0,e=255,f=150

    those are the numbers and they're values, u have to add the numbers according to the following ecuasion:

    0.9*x + 0.1*y = z

    where x is the main number that u can chose freely between the 3 numbers above, and y is the second number, chose freely again between the 3 numbers above.
    So to each one of the 3 values of the number the ecuation is applyed individual

    after that Z will become the main number and u'll be able to chose freely on the Y number from the 3 numbers mentioned above, continueing with the ecuation until the 3 values of Z will be these: d=148,e=156,f=137

    I'll make an example

    0.9*a + 0.1*c = d where d has the next values: d=135,e=25.5,f=244.5

    0.9*d + 0.1*a =f where f has the next values: d=136.5,e=22.95,f=243

    0.9*f + 0.1*b = g where g has the next values d=145.35,e=35.655,f=218.7

    and so on

    have fun

    don't forget, the final number msut have these values : d=148,e=156,f=137
    Last edited by NightM4k3r; January 7th 2010 at 11:32 AM.
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  2. #2
    MHF Contributor Drexel28's Avatar
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    Quote Originally Posted by NightM4k3r View Post
    as the title sez i have a challange, altho for some of you won't be really a challange, more like a walk in the park type of thing, here it goes:

    there are 3(a,b,c) numbers and each number has 3 values(d,e,f) as follows:

    a: d=150,e=0,f=255
    b: d=255,e=150,f=0
    c: d=0,e=255,f=150

    those are the numbers and they're values, u have to add the numbers according to the following ecuasion:

    0.9*x + 0.1*y = z

    where x is the main number that u can chose freely between the 3 numbers above, and y is the second number, chose freely again between the 3 numbers above.
    So to each one of the 3 values of the number the ecuation is applyed individual

    after that Z will become the main number and u'll be able to chose freely on the Y number from the 3 numbers mentioned above, continueing with the ecuation until the 3 values of Z will be these: d=148,e=156,f=137

    I'll make an example

    0.9*a + 0.1*c = d where d has the next values: d=135,e=25.5,f=244.5

    0.9*d + 0.1*a =f where f has the next values: d=136.5,e=22.95,f=243

    0.9*f + 0.1*b = g where g has the next values d=145.35,e=35.655,f=218.7

    and so on

    have fun

    don't forget, the final number msut have these values : d=148,e=156,f=137
    Hello, NightMaker! You're problem should belong in the puzzle section!
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  3. #3
    Super Member
    Joined
    Jan 2009
    Posts
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    Quote Originally Posted by NightM4k3r View Post
    as the title sez i have a challange, altho for some of you won't be really a challange, more like a walk in the park type of thing, here it goes:

    there are 3(a,b,c) numbers and each number has 3 values(d,e,f) as follows:

    a: d=150,e=0,f=255
    b: d=255,e=150,f=0
    c: d=0,e=255,f=150

    those are the numbers and they're values, u have to add the numbers according to the following ecuasion:

    0.9*x + 0.1*y = z

    where x is the main number that u can chose freely between the 3 numbers above, and y is the second number, chose freely again between the 3 numbers above.
    So to each one of the 3 values of the number the ecuation is applyed individual

    after that Z will become the main number and u'll be able to chose freely on the Y number from the 3 numbers mentioned above, continueing with the ecuation until the 3 values of Z will be these: d=148,e=156,f=137

    I'll make an example

    0.9*a + 0.1*c = d where d has the next values: d=135,e=25.5,f=244.5

    0.9*d + 0.1*a =f where f has the next values: d=136.5,e=22.95,f=243

    0.9*f + 0.1*b = g where g has the next values d=145.35,e=35.655,f=218.7

    and so on

    have fun

    don't forget, the final number msut have these values : d=148,e=156,f=137
    Couly you clarify what you are trying to do?

    I'm not sure which are variables and which are constants.
    It is not clear that the d in one line means the same d as previously defined for a value of d or if d actually is changed simultaneously for all d, when any d is changed.
    Is that part of the puzzle?

    OR
    is this what you intend:

    a_1=150 : a_2=0 : a_3= 255
    b_1=255 : b_2= 150: b_3= 0
    c_1= 0 : c_2= 255: c_3= 150

    d_1= 0.9*a_1 + 0.1*c_1 = 135
    d_2= 0.9*a_2 + 0.1*c_2 = 25.5
    d_3= 0.9*a_3 + 0.1*c_3 = 244.5

    [no formula for e]

    f_1= 0.9*d_1 + 0.1*a_1 = 136.5
    f_2= 0.9*d_2 + 0.1*a_2 = 22.95
    f_3= 0.9*d_3 + 0.1*a_3 = 243 How? 245.55 seems possible.

    g_1= 0.9*f_1 + 0.1*b_1 = 145.35 How? 148.35?
    g_2= 0.9*f_2 + 0.1*b_2 = 35.655 ok
    g_3= 0.9*f_3 + 0.1*b_3 = 218.7

    is this valid for h?
    h_1= 0.9*a_1 + 0.1*b_1 = 160.50
    h_2= 0.9*a_2 + 0.1*b_2 = 15.00
    h_3= 0.9*a_3 + 0.1*b_3 = 229.55

    would this be valid for h?
    h_1= 0.9*a_1 + 0.1*d_1 = 28.50
    h_2= 0.9*b_2 + 0.1*f_2 = 17.295
    h_3= 0.9*c_3 + 0.1*g_3 = 36.87

    or this?
    h_1= 0.9*a_1 + 0.1*a_1 = 150.00
    h_2= 0.9*a_2 + 0.1*a_2 = 0.00
    h_3= 0.9*a_3 + 0.1*a_3 = 255.00

    or this?
    h_1= 0.9*a_1 + 0.1*b_1 = 160.50
    h_2= 0.9*a_1 + 0.1*b_1 = 160.50
    h_3= 0.9*a_1 + 0.1*b_1 = 160.50

    Code:
     u'll be able to chose freely on the Y number from the 3 numbers mentioned above
    horizontally 3 numbers or vertically three numbers?

    Since you have 150 & 255 & 0 defined in the first column and at some point you want 148 in the first column, then
    You will need some combination of r,s,t,u to get the result.

    135.5r + 0.15s + 229.5t + 25.5u = 148

    r,s,t,u can be positive or negative.
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