# problem puzzler

• Oct 27th 2005, 09:45 AM
laura
how can i arrive at the number 679 only using the numbers 50,2,6,5,7,1,(all numbers can only be used once) Thanks if u can help me.
• Oct 28th 2005, 07:28 AM
hpe
Quote:

Originally Posted by laura
how can i arrive at the number 679 only using the numbers 50,2,6,5,7,1,(all numbers can only be used once) Thanks if u can help me.

$\displaystyle 2 \cdot 50 \cdot 7 - 6 \cdot 5 + 1$
• Oct 28th 2005, 08:40 AM
laura
sorry ten off please try again
• Oct 28th 2005, 04:21 PM
hpe
Quote:

Originally Posted by laura
sorry ten off please try again

Right you are ... use the 6 and the 7, and make a 9 from $\displaystyle 50/5 +1 -2$
• Oct 28th 2005, 06:01 PM
MathGuru
that's cute:p
• Oct 30th 2005, 08:05 AM
laura
sorry i mean 6 hundred and seventy nine from 50, 6, 7, 2, 1,3 :)
• Oct 30th 2005, 03:50 PM
MathGuru
here you go
(2*50*7)-((6+1)*3)
• Oct 31st 2005, 08:12 AM
laura
I have done it!!!!!!!!
i mean 50, 6, 7, 2, 1, 5. the answer is
50-1=49 49x2=98 6-5=1
98-1=97 97x7=679 :D
• Oct 31st 2005, 11:25 AM
MathGuru
You keep changing the problem
you are ridiculous.