# A number puzzle for u

• Oct 11th 2009, 02:09 PM
jeremyparker10
A number puzzle for u
There are two numbers with the difference of 3 between them and the difference of their squares is 51.
Can you find the numbers???
• Oct 11th 2009, 02:23 PM
Bruno J.
Spoiler:
Suppose the two numbers are \$\displaystyle a\$ and \$\displaystyle b\$, with \$\displaystyle a<b\$.

Then the problem says that \$\displaystyle b-a=3\$ and \$\displaystyle b^2-a^2=51\$. Note that \$\displaystyle b^2-a^2=(b-a)(b+a)\$. Can you finish now?
• Oct 11th 2009, 06:30 PM
mr fantastic
Quote:

Originally Posted by Bruno J.
Suppose the two numbers are \$\displaystyle a\$ and \$\displaystyle b\$, with \$\displaystyle a<b\$.

Then the problem says that \$\displaystyle b-a=3\$ and \$\displaystyle b^2-a^2=51\$. Note that \$\displaystyle b^2-a^2=(b-a)(b+a)\$. Can you finish now?

I suspect the OP was meant to be a challenge question (which is why the thread was moved to here and why I put spoiler tags around your reply).
• Oct 12th 2009, 02:21 AM
jeremyparker10
@ Bruno: yes you are right,,,

• Oct 12th 2009, 07:19 AM
HallsofIvy
Quote:

Originally Posted by mr fantastic
I suspect the OP was meant to be a challenge question (which is why the thread was moved to here and why I put spoiler tags around your reply).

Then why post his solution immediately below?
• Oct 12th 2009, 12:56 PM
jeremyparker10
X = 10
y = 7
• Oct 12th 2009, 02:51 PM
mr fantastic
Quote:

Originally Posted by HallsofIvy
Then why post his solution immediately below?

I didn't want to delete the reply on the one hand but I didn't want the reply to be in plain sight on the other hand. So my third hand decided a good compromise would be to put spoiler tags around it.
• Oct 12th 2009, 09:37 PM
Wilmer
Quote:

Originally Posted by mr fantastic
So my third hand decided a good compromise would be to put spoiler tags around it.

Is 3 hands what makes you "fantastic"? (Giggle)