$\displaystyle x_n \stackrel{n \to\infty}{\longrightarrow} x_\infty$

Printable View

- May 1st 2010, 04:02 AMMoo
$\displaystyle x_n \stackrel{n \to\infty}{\longrightarrow} x_\infty$

- May 1st 2010, 05:06 AMOpalg
One advantage of \overset over \stackrel is that there is a corresponding command \underset, so that you can write $\displaystyle x_n \underset{n \to\infty}{\longrightarrow} x_\infty$. You can even combine the two, to get things like $\displaystyle x_n \underset{\text{Moo}}{\overset{n \to\infty}{\longrightarrow}} x_\infty$ (if ever you should wish to).

- May 1st 2010, 05:58 AMMoo
There is also $\displaystyle \text{LaTeX} \xrightarrow[Opalg] {age \to 100} \text{perfection}$

XD

I agree, I prefer overset :) I just wanted to show another way (until I remembered xrightarrow) - May 1st 2010, 07:42 AMOpalg