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Math Help - n00b Testing Latex

  1. #1
    Newbie beardedoneder's Avatar
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    n00b Testing Latex

    Given: f(x)=x+2, h(x)=\frac{1}{x-1}
    Find \frac{[h(x)]^2}{f(x)}, and list domain restrictions
    \frac{[\frac{1}{x-1}]^2}{x+2} = \frac{\frac{1}{(x-1)(x-1)}}{\frac{x+2}{1}} = \frac{1}{(x-1)(x-1)} \bullet \frac{1}{x+2} =
    \frac{1}{(x-1)(x-1)(x+2)}, x \neq \{1,-2\}
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  2. #2
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    earboth's Avatar
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    Quote Originally Posted by beardedoneder View Post
    Given: f(x)=x+2, h(x)=\frac{1}{x-1}
    Find \frac{[h(x)]^2}{f(x)}, and list domain restrictions
    \frac{[\frac{1}{x-1}]^2}{x+2} = \frac{\frac{1}{(x-1)(x-1)}}{\frac{x+2}{1}} = \frac{1}{(x-1)(x-1)} \bullet \frac{1}{x+2} =
    \frac{1}{(x-1)(x-1)(x+2)}, x \neq \{1,-2\}
    Only one tip: Instead of \bullet us \cdot

    \frac{1}{(x-1)(x-1)} \cdot \frac{1}{x+2}
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