Find 3 consecutive even integers such that the square of the largest number is 124 more than the square of the second largest number.

Let your 3 numbers equal X, X+2 and X+4 (because of the even integer boundary)

So, According to the problem, <largest number squared> <second number squared>

Expand:

Simplify both sides of the equations by removing the integers (+16 and -4 to the 124):

Take -112 to the right side to become positive:

Minus and solve for x:

add original formulas to get the final 3 even integers of28, 30, and 32!