Find 3 consecutive even integers such that the square of the largest number is 124 more than the square of the second largest number.
Let your 3 numbers equal X, X+2 and X+4 (because of the even integer boundary)
So, According to the problem, <largest number squared> <second number squared>
Simplify both sides of the equations by removing the integers (+16 and -4 to the 124):
Take -112 to the right side to become positive:
Minus and solve for x:
add original formulas to get the final 3 even integers of 28, 30, and 32!