# LaTeX Testing

• Jul 30th 2008, 05:21 AM
Jones
LaTeX Testing
$\displaystyle \sqrt{x-2} \cdot \sqrt{x-5} = (x-2)^\frac{1}{2} \cdot (x-5)^\frac{1}{2}$
$\displaystyle a^{b} \cdot b^{a} = ab^{a+b}$
$\displaystyle (x-2)^\frac{1}{2} \cdot (x-5)^\frac{1}{2}$
$\displaystyle (x^2-7x-10)^\frac{1}{2} + ^\frac{1}{2}$
• Jul 30th 2008, 05:30 AM
Jones
hmm, how do i add fractions together in a proper way?
• Jul 30th 2008, 05:43 AM
flyingsquirrel
Hi
Quote:

Originally Posted by Jones
hmm, how do i add fractions together in a proper way?

What do you call "a proper way" ? Something like $\displaystyle \frac{a}{b}+\frac{c}{d}=42$ ? (click on the formula to see the code I typed)
• Jul 30th 2008, 05:45 AM
Jones
Quote:

Originally Posted by flyingsquirrel
Hi

What do you call "a proper way" ? This : $\displaystyle \frac{a}{b}+\frac{c}{d}=42$ ? (click on the formula to see the code I typed)

Yes i know, but i want to add two fractions as raised to the power of X
• Jul 30th 2008, 05:58 AM
flyingsquirrel
Quote:

Originally Posted by Jones
Yes i know, but i want to add two fractions as raised to the power of X

$\displaystyle \left( \frac{x-2}{8} \right)^2 \cdot \left( \frac{x-5}{8} \right)^2= \frac{(x-2)^2(x-5)^2}{8^4}$ ? Let me know if it is -still- not what you meant. :D
• Jul 30th 2008, 06:02 AM
Jones
Hi,

No, i want to add 1/2 + 1/2 in raised form. Like X^1/2 + 1/2
• Jul 30th 2008, 06:14 AM
flyingsquirrel
Quote:

Originally Posted by Jones
No, i want to add 1/2 + 1/2 in raised form. Like X^1/2 + 1/2

OK, I think I've understood : $\displaystyle x^{\frac{1}{2}+\frac{1}{2}}$
• Jul 30th 2008, 06:15 AM
Jones
Yes, thank you :)
• Jul 30th 2008, 06:33 AM
arbolis
Also useful maybe : $\displaystyle \sqrt[4]{x^3}=x^{\frac{3}{4}}$.
• Jul 30th 2008, 10:49 AM
dashreeve
testing $\displaystyle \alpha\beta\frac{2x^2-4}{\sqrt{a^2-bx^2}}$