Testing LaTeX 2

**flyingsquirrel** · October 11th 2008, 11:40 AM

Originally Posted by Jones

Hehe, how would i get a left bracket first to indicate an equation system, (or congruence system if you like)

Try this :

$\begin{cases} \phi(n) \equiv q \pmod{42} \\ p \equiv n \pmod{234^{432}} \\ \end{cases}$

If you want to have the symbols $\equiv$ aligned you can use the command & :

$\begin{cases} \phi(n) & \equiv q \pmod{42} \\ p & \equiv n \pmod{234^{432}} \\ \end{cases}$

If you don't want $q$ and $\phi(n)$ to be aligned on the left, you'll have to use an array instead of the cases environment :

$ \left\{ \begin{array}{ccl} \phi(n) & \equiv & q \pmod{42} \\ p & \equiv & n \pmod{234^{432}} \\ \end{array} \right. $

$ \left\{ \begin{array}{rcl} \phi(n) & \equiv & q \pmod{42} \\ p & \equiv & n \pmod{234^{432}} \\ \end{array} \right. $

**masters** · October 19th 2008, 01:16 PM

What do you use for the arc symbol? I've been using

\widehat{ABC} to get $\widehat{ABC}$ , but that's not quite it.

I tried using: \stackrel{\frown}{ABC}

$\stackrel{\frown}{ABC}$

That just doesn't look right, either. It's too small.

**Opalg** · October 20th 2008, 06:15 AM

Originally Posted by masters

What do you use for the arc symbol? I've been using

\widehat{ABC} to get $\widehat{ABC}$ , but that's not quite it.

I tried using: \stackrel{\frown}{ABC}

$\stackrel{\frown}{ABC}$

That just doesn't look right, either. It's too small.

You can make it slightly bigger by \stackrel{\textstyle\frown}{ABC}:

$\stackrel{\textstyle\frown}{ABC}$

**masters** · October 21st 2008, 01:12 PM

Originally Posted by Opalg

You can make it slightly bigger by \stackrel{\textstyle\frown}{ABC}:

$\stackrel{\textstyle\frown}{ABC}$

Yeah, that'd be ok for minor arcs like $\stackrel{\textstyle\frown}{AB}$

**Mathstud28** · November 23rd 2008, 05:54 PM

Let $X$ be a metric space, and let $E\subset{X}$ . Now define $S\equiv\left\{d(p,q):q,p\in{E}\right\}$ , now if $\sup\left(S\right)=\gamma$ we may equivalently write $\diam\left(E\right)=\gamma$ ...Is ther a code that gives $\text{diam}\left(E\right)$ ?

**Chris L T521** · November 23rd 2008, 06:18 PM

Originally Posted by Mathstud28

Let $X$ be a metric space, and let $E\subset{X}$ . Now define $S\equiv\left\{d(p,q):q,p\in{E}\right\}$ , now if $\sup\left(S\right)=\gamma$ we may equivalently write $\diam\left(E\right)=\gamma$ ...Is ther a code that gives $\text{diam}\left(E\right)$ ?

From what I know, no. One can define this command...but you can't do so here on MHF. If you had a LaTeX editor [like TeXnic Center], you can post the following into the preamble of the document:

Code:

\newcommand{\diam}[1]{\text{diam}\left(#1\right)}

And then when you type \diam E, it gives you $\text{diam}\left(E\right)$

--Chris

**Mathstud28** · November 23rd 2008, 06:20 PM

Originally Posted by Chris L T521

From what I know, no. One can define this command...but you can't do so here on MHF. If you had a LaTeX editor [like TeXnic Center], you can post the following into the preamble of the document:

Code:

\newcommand{\diam}[1]{\text{diam}\left(#1\right)}

And then when you type \diam E, it gives you $\text{diam}\left(E\right)$

--Chris

Haha, that is a lot of work. I think I will just stick with $\text{diam}\left(E\right)$

Thanks though!

**flyingsquirrel** · November 25th 2008, 01:07 AM

$\begin{pmatrix} a_{1,1} & a_{2,1} & \ldots & a_{n,1}\\ a_{2,1} & a_{2,2} & \ldots & a_{n,2}\\ \hdotsfor[1.7]{4}\\ a_{n,1} & a_{2,n} & \ldots & a_{n,n} \end{pmatrix}$

$\begin{pmatrix} a_{1,1} & a_{2,1} & \ldots & a_{n,1}\\ a_{2,1} & a_{2,2} & \ldots & a_{n,2}\\ \vdots & \vdots & \ddots & \vdots \\ a_{n,1} & a_{2,n} & \ldots & a_{n,n} \end{pmatrix}$

**Chris L T521** · November 29th 2008, 01:27 PM

$ \begin{matrix}0&1\\1&0\end{matrix} \hspace{1.5pc} \begin{pmatrix}0&1\\1&0\end{pmatrix} \hspace{1.5pc} \begin{bmatrix}0&1\\1&0\end{bmatrix} \hspace{1.5pc} \begin{Bmatrix}0&1\\1&0\end{Bmatrix} \hspace{1.5pc} \begin{vmatrix}0&1\\1&0\end{vmatrix} \hspace{1.5pc} \begin{Vmatrix}0&1\\1&0\end{Vmatrix} $

**Greengoblin** · December 2nd 2008, 02:28 AM

$\sum_{k=0}^n$

$\sum_{k=0}^n a^k$

$\sum_{r=0}^n a^r$

$ \sum_{r=0}^n\ ^nC_r a^r$

$\sum_{r=0}^n ^nC_r a^rb^{n-r}$

$(x+y)^n$

$$x+y$^n$

**iLikeMaths** · December 13th 2008, 07:36 PM

$ -e^{-x^2} $

equals 0

**Mathstud28** · December 31st 2008, 12:33 AM

$\int\limits_-\cdots \int\limits_\text{ }^-\cdots\int\limits_a^b$

Math $\int\limits_- f~d\alpha=\sup_{P}L\left(P,f,\alpha\right)$

**Soroban** · December 31st 2008, 05:18 PM

. . . $\frac{1{\color{red}\rlap{/}}6}{{\color{red}\rlap{/}}64} \;=\;\frac{1}{4} \qquad\qquad \frac{1{\color{red}\rlap{/}}9}{{\color{red}\rlap{/}}95} \;=\;\frac{1}{5}$ . . . . . $\frac{2{\color{red}\rlap{/}}6}{{\color{red}\rlap{/}}65} \;=\;\frac{2}{5}\qquad\qquad \frac{4{\color{red}\rlap{/}}9}{{\color{red}\rlap{/}}98} \;=\;\frac{4}{8}\;=\;\frac{1}{2}$

. . . . . $\frac{1-x^{{\color{red}\rlap{/}}2}}{(1+x)^{{\color{red}\rlap{/}} 2} }\;=\;\frac{1-x}{1+x}$

All that work for a bad joke . . .

(Good luck trying to read my LaTeX code.)
.

**Last_Singularity** · December 31st 2008, 06:27 PM

A fairly comprehensive guide to LaTeX here:

http://tobi.oetiker.ch/lshort/lshort.pdf

**galactus** · December 31st 2008, 06:54 PM

Just trying something fancy in LaTex. This came from that tutorial.

Thanks for that link.

$\text{Heron's formula}\setlength{\unitlength}{1cm} \begin{picture}(6,5) \thicklines \put(1,0.5){\line(2,1){3}} \put(4,2){\line(-2,1){2}} \put(2,3){\line(-2,-5){1}} \put(0.7,0.3){$A$} \put(4.05,1.9){$B$} \put(1.7,2.95){$C$} \put(3.1,2.5){$a$} \put(1.3,1.7){$b$} \put(2.5,1.05){$c$} \put(0.3,4){$F= \sqrt{s(s-a)(s-b)(s-c)}$} \put(3.5,0.4){$\displaystyle s:=\frac{a+b+c}{2}$} \end{picture}$

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