# arctan(x)

• June 2nd 2008, 04:21 PM
Mathstud28
arctan(x)
Why doesnt math]\arctan(x)[/tex] yield a version that is not italicized, is it not a function, it says it is on LaTeX websites

The same goes for any inverse trigonometric or hyperbolic functions
• June 2nd 2008, 04:32 PM
Jhevon
Quote:

Originally Posted by Mathstud28
Why doesnt math]\arctan(x)[/tex] yield a version that is not italicized, is it not a function, it says it is on LaTeX websites

The same goes for any inverse trigonometric or hyperbolic functions

i guess the syntax is off. \arctan x works ... $\arctan x$ see?

it is just the way the codes are set up. no parentheses :p
• June 2nd 2008, 07:55 PM
CaptainBlack
Quote:

Originally Posted by Mathstud28
Why doesnt math]\arctan(x)[/tex] yield a version that is not italicized, is it not a function, it says it is on LaTeX websites

The same goes for any inverse trigonometric or hyperbolic functions

$$\arctan(x)$$ produces:

$\arctan(x)$

RonL
• June 2nd 2008, 08:13 PM
Mathstud28
Quote:

Originally Posted by CaptainBlack
$$\arctan(x)$$ produces:

$\arctan(x)$

RonL

Hmm...I think you are magic CaptainBlack, for it did not work before...well anyways

$\arctan(x)!$....and thats happiness..not factorials xD

$\arctanh(x)$ $\leftarrow$ what about arctanh?
• June 2nd 2008, 08:17 PM
Jhevon
Quote:

Originally Posted by Mathstud28
Hmm...I think you are magic CaptainBlack, for it did not work before...well anyways

$\arctan(x)!$....and thats happiness..not factorials xD

what were you doing?! :p you probably had a typo in the arctan itself
• June 2nd 2008, 08:20 PM
Mathstud28
Quote:

Originally Posted by Jhevon
what were you doing?! :p you probably had a typo in the arctan itself

shut up...(Sun)
• June 2nd 2008, 08:51 PM
CaptainBlack
Quote:

Originally Posted by Mathstud28
Hmm...I think you are magic CaptainBlack, for it did not work before...well anyways

$\arctan(x)!$....and thats happiness..not factorials xD

$\arctanh(x)$ $\leftarrow$ what about arctanh?

arctanh is not on the standard list of functions so you have to do it the hardway:

$${\rm{arctanh}}(x)$$

${\rm{arctanh}}(x)$

RonL