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Thread: how do you skip lines?

  1. #1
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    how do you skip lines?

    Using LaTex, how do you skip lines within the same [tex] bracket? for example:
    $\displaystyle cos(x)$
    $\displaystyle sin(x)$
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  2. #2
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    Quote Originally Posted by lllll View Post
    Using LaTex, how do you skip lines within the same [tex] bracket? for example:
    $\displaystyle cos(x)$
    $\displaystyle sin(x)$
    As you do not have a single pair of delimiters here just put a blank line between the lines:


    [tex]cos(x)[/tex]

    [tex]sin(x)[/tex]


    produces:

    $\displaystyle cos(x)$

    $\displaystyle sin(x)$

    and:

    [maTH]
    \begin{array}{l}
    \cos (x) \\ \\
    \sin (x) \\
    \end{array}
    [/tex]

    produces:

    [maTH]
    \begin{array}{l}
    \cos (x) \\ \\
    \sin (x) \\
    \end{array}
    [/tex]

    RonL
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    Re: how do you skip lines?

    Huh? So, the beginning tag is "maTH" but the ending tag is "tex"? Let me try:
    [maTH]x = 3
    y = 2
    z = 4[/tex]
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  4. #4
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    Re: how do you skip lines?

    Quote Originally Posted by Monoxdifly View Post
    Huh? So, the beginning tag is "maTH" but the ending tag is "tex"? Let me try:
    [maTH]x = 3
    y = 2
    z = 4[/tex]
    Why are you replying to a post from eleven years ago?
    Thanks from topsquark
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    Forum Admin topsquark's Avatar
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    Re: how do you skip lines?

    Quote Originally Posted by lllll View Post
    Using LaTex, how do you skip lines within the same [tex] bracket? for example:
    $\displaystyle cos(x)$
    $\displaystyle sin(x)$
    Use a \\ between what you want to split into more than one line.
    [tex]cos(x) \\ sin(x) [/tex]

    gives
    $\displaystyle cos(x) \\ sin(x) $

    -Dan
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    Re: how do you skip lines?

    If you want more space use, for example
    Code:
    \\[12pt]
    $\displaystyle \cos x \\[12pt] \sin x$
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    Re: how do you skip lines?

    Quote Originally Posted by Plato View Post
    Why are you replying to a post from eleven years ago?
    Once I asked the admin if necro-posting was allowed and he said that it is.

    Now, let me try again:
    $\displaystyle sin x\\cos x$
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