What is the cancel package?

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- Jul 13th 2007, 10:03 AMMathGuru
- Jul 13th 2007, 10:22 AMKrizalid
Nope, I just saw it somewhere and really looks cool :D:D

You can use \mathop{{\int\!\!\!\!\!\int}\mkern-21mu\bigcirc}{}

This yields $\displaystyle \mathop{{\int\!\!\!\!\!\int}\mkern-21mu\bigcirc}{}$

I mean

http://www.rinconmatematico.com/foro...805ed4e2ff.gif - Jul 13th 2007, 02:02 PMred_dog
How can I insert an image in my post?

I used the "Insert image " button, but one ask me to introduce the URL and the image is in my own computer. - Jul 13th 2007, 02:05 PMKrizalid
You can use ImageShack

It's the best way to upload & plug the images to the forum :D:D - Jul 13th 2007, 03:42 PMgalactus
- Jul 13th 2007, 03:58 PMred_dog
But I don't find "Manage attachments".

- Jul 13th 2007, 04:23 PMgalactus
Really?. That's odd. It's there when I click "post reply". Scroll down to it. That doesn't make sense.

It's right beneath where you write your post. Under "Additional Options", "Attach Files". There's a icon bar that reads "Manage Attachmants". - Jul 29th 2007, 02:43 PMThePerfectHacker
Is it possible to create the command

Code:`\gal`

Instead of writing,

Code:`\mbox{Gal}`

I have more such commands which I end up using. So if it possible I can create a list. - Jul 29th 2007, 02:47 PMKrizalid
I think it's possible to set a command like that.

You can also write in text using \text

Not hard.

P.S.: or for some special commands, using \mathrm - Jul 29th 2007, 03:00 PMtukeywilliams
Is Texnic Center good for writing LaTeX files?

- Jul 29th 2007, 03:10 PMKrizalid
Yeah, good software :)

- Jul 29th 2007, 03:27 PMJakeD
- Jul 31st 2007, 09:18 PMDean
Can someone please give me the code for:

1. 3^(3x +4).18^(-x-2)/24^(x+3).4^(-2x-1)

2. 21^(3x+1).7(2-x)/49^(x-1).27^(x-4)

Thanks in advance. - Jul 31st 2007, 10:30 PMCaptainBlack
3^(3x +4).18^(-x-2)/24^(x+3).4^(-2x-1)

$\displaystyle \frac{3^{3x +4}.18^{-x-2}}{24^{x+3}.4^{-2x-1}}$

which is generated by:

[tex]\frac{3^{3x +4}.18^{-x-2}}{24^{x+3}.4^{-2x-1}}[/tex]

21^(3x+1).7(2-x)/49^(x-1).27^(x-4)

$\displaystyle \frac{21^{3x+1}.7^{2-x}}{49^{x-1}.27^{x-4}}$

which is generated by:

[tex]\frac{21^{3x+1}.7^{2-x}}{49^{x-1}.27^{x-4}}[/tex]

RonL - Aug 1st 2007, 12:00 AMDean
Thanks a million.