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Math Help - How do I get these Equations aligned?

  1. #1
    Junior Member
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    How do I get these Equations aligned?

    $\frac{dP}{dr}=\frac{-\Big(P+\rho (P)c^2 \Big)} {2} \frac {d\nu} {dr}\]$\\
    \newline
    $$\Rightarrow d\nu = \frac {-2dP} {P+\rho (P) c^2}$$\\
    \bigskip \newline
    $$ \nu (r) = - \int_{0}^{P(r)} \frac {2dP}{P+\rho (P) c^2} + \nu (r_b)$$
    \newline
    \newline
    \newline
    $$ e^{\nu(r)} &= e^{\nu(r_b) - \int_{0}^{P(r)} \frac {2dP}{P+\rho (P) c^2} }$$
    \newline




    $$ e^ {\nu (r)}= e^{\nu(r_b)} exp \Big[-\int_{0}^{P(r)} \frac {2dP}{P+\rho (P) c^2} \Big]$$

    I am new to LaTex, so my codes look very childish, anyway someone please help me put these aligned
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  2. #2
    MHF Contributor
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    Re: How do I get these Equations aligned?

    $\begin{align*}

    &\frac{dP}{dr}=\frac{-\Big(P+\rho (P)c^2 \Big)} {2} \frac {d\nu} {dr} \Rightarrow
    \\ \\
    & d\nu = \frac {-2dP} {P+\rho (P) c^2}
    \\ \\

    &\nu (r) = - \int_{0}^{P(r)} \frac {2dP}{P+\rho (P) c^2} + \nu (r_b)
    \\ \\

    &\large e^{\nu(r)} = e^{\nu(r_b) - \int_{0}^{P(r)} \frac {2dP}{P+\rho (P) c^2} }
    \\ \\

    &\large e^ {\nu (r)}= e^{\nu(r_b)} exp \Big[-\int_{0}^{P(r)} \frac {2dP}{P+\rho (P) c^2} \Big]

    \end{align*}$

    This do it for you?
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  3. #3
    Junior Member
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    Re: How do I get these Equations aligned?

    thanks a lot
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