I take it the reason the \sum operator gives different "vertical" formats in the fractions than outside is to save space or something?
That is
vs
-Dan
Hey Dan,
I recently learned (at MHB) to use the \limits command to force the limits of sums and products to display where I want. The code:
r = \sqrt{1 - \frac{ \sum\limits_{i = 1}^n ( y_i - yf_i )^2 }{ \sum\limits_{i = 1}^n (y_i - \bar{y} )^2 }}
produces: