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Math Help - \sum + fractions

  1. #1
    Forum Admin topsquark's Avatar
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    \sum + fractions

    I take it the reason the \sum operator gives different "vertical" formats in the fractions than outside is to save space or something?
    That is
    r = \sqrt{1 - \frac{ \sum_{i = 1}^n ( y_i - yf_i )^2 }{ \sum_{i = 1}^n (y_i - \bar{y} )^2 }}

    vs
    \sum_{i = 1}^n

    -Dan
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  2. #2
    MHF Contributor MarkFL's Avatar
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    Re: \sum + fractions

    Hey Dan,

    I recently learned (at MHB) to use the \limits command to force the limits of sums and products to display where I want. The code:

    r = \sqrt{1 - \frac{ \sum\limits_{i = 1}^n ( y_i - yf_i )^2 }{ \sum\limits_{i = 1}^n (y_i - \bar{y} )^2 }}

    produces:

    r = \sqrt{1 - \frac{ \sum\limits_{i = 1}^n ( y_i - yf_i )^2 }{ \sum\limits_{i = 1}^n (y_i - \bar{y} )^2 }}
    Thanks from topsquark
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