# Algebraic Fraction

• Jul 3rd 2013, 10:07 AM
Seaniboy
Algebraic Fraction
Hi,

If Y = 3x+2/5-x, express x in terms of y.

Thank you.
• Jul 3rd 2013, 10:59 AM
ebaines
Re: Algebraic Fraction
Please clarify: do yuo mean $\displaystyle Y = 3x + \frac 2 5 -x$ (which is what you wrote), or do you mean $\displaystyle Y= \frac {3x+2}{5-x}$ ? Or perhaps $\displaystyle Y=\frac {3x + 2} 5 - x$?

Or perhaps since you posted your question in the LaTeX help section you're looking for asistance in writing the equation as I did, using LaTeX?
• Jul 4th 2013, 12:45 PM
Seaniboy
Re: Algebraic Fraction
Hi,
Y = 3X + 2 divided by 5 - x as per the second option in your post.

Apologies for not using latex. Yes, I would like help, if possible, in using latex. I am using a mac - if that's relevant.
Sean.
• Jul 4th 2013, 01:08 PM
Plato
Re: Algebraic Fraction
Quote:

Originally Posted by Seaniboy
Hi,
Y = 3X + 2 divided by 5 - x as per the second option in your post.
Apologies for not using latex. Yes, I would like help, if possible, in using latex. I am using a mac - if that's relevant.

The platform you use is irrelevant. LaTeX is a function of the webpage.

[TEX] \frac{3x+2}{5-x} [/TEX] gives $\displaystyle \frac{3x+2}{5-x}$.

This subforum will help you with the code. Once you begin, you quickly learn the code. If you click on the “go advanced tab” you should see $\displaystyle \boxed{\Sigma}$ on the tool-bar. That gives the [TEX]..[/TEX] wrap. Your LaTeX code goes between them.

Here are more examples:
[TEX](5+2\sqrt{6})^{x^2-3}+(5-2\sqrt{6})^{x^2-3} [/TEX] gives $\displaystyle (5+2\sqrt{6})^{x^2-3}+(5-2\sqrt{6})^{x^2-3}$
• Jul 4th 2013, 02:39 PM
HallsofIvy
Re: Algebraic Fraction
As for your problem, to solve y= (3x+2)/(5- x) for x, start by multiplying both sides by 5- x.
• Jul 8th 2013, 06:14 AM
Seaniboy
Re: Algebraic Fraction
Hi,
Ho capito. Thanks a lot.
Seaniboy.
• Jul 8th 2013, 06:15 AM
Seaniboy
Re: Algebraic Fraction
Thanks a lot.
Sean