Testing LaTeX

**Moo** · April 26th 2008, 11:19 PM

${\color{blue} Dark green}$
${\color{cyan} Purple}$
${\color [cmyk] {1,1,0,0.5} Brown}$
${\color{white} Dark Blue}$
${\color{green} Grey}$
${\color [cmyk] {0.75,0,0.75,0.45} Orange}$
${\color{magenta} Magenta}$
${\color{red} Green}$
${\color[gray]{0.5} Red}$
${\color{yellow} Blue}$
${\color[rgb] {.5,0,1} Yellow}$
${\color [cmyk] {0,.35,1,0} White}$
${\color [cmyk] {0.4,.75,0.8,0} Cyan}$

**Jhevon** · April 26th 2008, 11:30 PM

Originally Posted by Moo

${\color{blue} Dark green}$
${\color{cyan} Purple}$
${\color [cmyk] {1,1,0,0.5} Brown}$
${\color{white} Dark Blue}$
${\color{green} Grey}$
${\color [cmyk] {0.75,0,0.75,0.45} Orange}$
${\color{magenta} Magenta}$
${\color{red} Green}$
${\color[gray]{0.5} Red}$
${\color{yellow} Blue}$
${\color[rgb] {.5,0,1} Yellow}$
${\color [cmyk] {0,.35,1,0} White}$
${\color [cmyk] {0.4,.75,0.8,0} Cyan}$

Obviously you're bored. Go and find something constructive to do

**Moo** · April 26th 2008, 11:38 PM

I'm doing

This was just a test... But a psy test

**Danshader** · April 27th 2008, 10:35 PM

is there a software program where i can test out latex? o.o it will be messy if i keep on posting in here just to test out latex.

**Moo** · April 27th 2008, 11:52 PM

Hi Danshader,

I know this site : LaTeX

However, it's in French, but I think it's still understandable.
Plus, there are some codes they don't know there, and that we use here.

**Danshader** · April 28th 2008, 12:05 AM

xD it works just fine just that i don't have to put the [tex] tags

**Moo** · April 28th 2008, 12:08 AM

Of course not ^^

And you can see that you can take the pictures of the things you've written.
The problem is that when you validate your writing, you can't get the code back, so it's better copying before validating

**Danshader** · April 28th 2008, 12:15 AM

i realized that thanks for reminding o.o"

**Moo** · May 1st 2008, 12:40 AM

Testing weird stuff

$\begin{aligned} 1 \\ 1 & 1 \\ 2 & 1 \\ 1 & 2 & 1 & 1 \\ \dots \end{aligned}$

$\begin{aligned} I & =\int_0^\pi \cos(\theta) d\theta \\ &=0 \end{aligned}$

Great

**Mathstud28** · May 1st 2008, 05:17 PM

Can someone please show me where I am messing up?

$f(x)=\left\{begin{array}{cc} ax^4-2x+3,&\mbox{ if } {0<x<12}\\ bx^2+3, & \mbox{ if } {12<x<15}\end{array}\right$

**o_O** · May 1st 2008, 05:32 PM

[tex]f(x)=\left\{ \begin{array}{cc} ax^4-2x+3,& \mbox{ if } {0<x<12}\\ bx^2+3, & \mbox{ if } {12<x<15}\end{array}\right.[/tex]

Two errors indicated in red. You missed the "\" before beginning array and you need a period at the very end (for some reason you need it when dealing with \left\{ ... \right. )

This gives :
$f(x)=\left\{ \begin{array}{cc} ax^4-2x+3,& \mbox{ if } {0<x<12}\\ bx^2+3, & \mbox{ if } {12<x<15}\end{array}\right.$

Personally, I'd align it to the left (replacing the c's with l's):
$f(x)=\left\{ \begin{array}{ll} ax^4-2x+3 & \mbox{ if } {0<x<12}\\ bx^2+3 & \mbox{ if } {12<x<15}\end{array}\right.$

**Mathstud28** · May 1st 2008, 05:40 PM

Originally Posted by o_O

[tex]f(x)=\left\{ \begin{array}{cc} ax^4-2x+3,& \mbox{ if } {0<x<12}\\ bx^2+3, & \mbox{ if } {12<x<15}\end{array}\right.[/tex]

Two errors indicated in red. You missed the "\" before beginning array and you need a period at the very end (for some reason you need it when dealing with \left\{ ... \right. )

This gives :
$f(x)=\left\{ \begin{array}{cc} ax^4-2x+3,& \mbox{ if } {0<x<12}\\ bx^2+3, & \mbox{ if } {12<x<15}\end{array}\right.$

Personally, I'd align it to the left (replacing the c's with l's):
$f(x)=\left\{ \begin{array}{ll} ax^4-2x+3 & \mbox{ if } {0<x<12}\\ bx^2+3 & \mbox{ if } {12<x<15}\end{array}\right.$

$f(x)=\left\{ \begin{array}{ll} 1, & \mbox{ if } {x\in\mathbb{Q}}\\ -1 & \mbox{ if }x\in\mathbb{Q}\end{array}\right.$

Hooray!

**Moo** · May 1st 2008, 11:42 PM

Hey oO

$f(x)={4<36}$

This is the code for the last one of o_O :

f(x)=\left\{ \begin{array}{ll} ax^4-2x+3 & \mbox{ if } {0<12}\\ bx^2+3 & \mbox{ if } {12<15}\end{array}\right.

How come the things in red yield 12<x<15 for example ?
And what does \right. stand for ?

**o_O** · May 2nd 2008, 09:48 AM

$f(x)=\left\{ \begin{array}{ll} ax^4-2x+3 & \mbox{ if } {0<12}\\ bx^2+3 & \mbox{ if } {12<15}\end{array}\right.$

That's weird .. I just copied Mathstud's code. It isn't working the second time around though ...

**flyingsquirrel** · May 2nd 2008, 10:44 AM

Originally Posted by Moo

f(x)=\left\{ \begin{array}{ll} ax^4-2x+3 & \mbox{ if } {0<12}\\ bx^2+3 & \mbox{ if } {12<15}\end{array}\right.

[...]

And what does \right. stand for ?

That's because every "\left" needs a matching "\right" but we don't want the right brace to appear.

For example, with parentheses (we only keep the right one) : $\left. \frac{\aleph_0}{42} \right)$
If you don't want any bracket, write $\left. \frac{\aleph_0}{42} \right.$

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