Testing LaTeX

**janvdl** · November 12th 2007, 08:00 AM

By the way:

\ creates a space in Latex when something doesn't immediately follow it.

For example

James Jarvis (with the [tex] wrapped around of course)

$James Jarvis$

But James \ Jarvis

$James \ Jarvis$

**james jarvis** · November 12th 2007, 08:03 AM

Sorry! Im trying to write v= K x ln(1/x) K being constant and x being algibraic x.

Thanks.

**janvdl** · November 12th 2007, 08:04 AM

Originally Posted by james jarvis

Sorry! Im trying to write v= K x ln(1/x) K being constant and x being algibraic x.

Thanks.

V = K \times ln( \frac{1}{x} )

$V = K \times ln( \frac{1}{x} )$

**james jarvis** · November 12th 2007, 08:08 AM

$V = K x ln( \frac{1}{x} )$

**Krizalid** · November 12th 2007, 08:16 AM

I'd write it as

$V=K\cdot\ln\frac1x.$ Or $V=K\times\ln\frac1x.$

Click on the LaTeX images to see their codes.

**janvdl** · November 12th 2007, 08:19 AM

Originally Posted by Krizalid

I'd write it as

$V=K\cdot\ln\frac1x.$ Or $V=K\times\ln\frac1x.$

Click on the LaTeX images to see their codes.

It seems both x's are letters, not a multiplication sign

**Jhevon** · November 12th 2007, 09:30 AM

Originally Posted by janvdl

V = K \times ln( \frac{1}{x} )

$V = K \times ln( \frac{1}{x} )$

use \ln as opposed to ln

and use \left( \frac 1x \right) as opposed to ( \frac 1x )

you will get $\ln \left( \frac 1x \right)$ which looks nicer than $ln( \frac 1x)$

personally, i like using ~ for space, so i'd type James~Jarvis

**PaulRS** · November 16th 2007, 01:25 PM

$f(x)|^b_a=f(b)-f(a)$

I'd like to know the correct code for the long bar

Thank you

**Soroban** · November 16th 2007, 01:48 PM

Hello, Paul!

$f(x)|^b_a=f(b)-f(a)$

I'd like to know the correct code for the long bar

I use: .f(x) \bigg | ^b _a

. . and get: . $f(x) \bigg|^b_a$

**Krizalid** · November 16th 2007, 02:10 PM

Originally Posted by PaulRS

$f(x)|^b_a=f(b)-f(a)$

I'd like to know the correct code for the long bar

**JoFaSs** · December 26th 2007, 03:33 PM

First time using LaTex and first post!
Testing...

$\frac {x^{n+1}}{x^{n-1}}$

$log_{7}7^k=k$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\int_{0}^{50}(x)=1250$

$f(x)=3+\frac{x-2}{x+3}$

$\frac{d}{dx}3x^k=3kx^{k-1}$

This is

**OzzMan** · February 5th 2008, 12:09 AM

$ \frac{\sqrt{3}}{2} $

**ecMathGeek** · February 5th 2008, 10:43 AM

$IFF~ \frac{d}{dx}F(x)=f(x)$ for $a\leq x\leq b$

$\lim_{n\rightarrow\infty}\sum^n_{i=1}{f\left(x+\le ft(\frac{b-a}{n}\right)i\right)}\left(\frac{b-a}{n}\right)~=~\int^b_a{f(x)}dx~=~F(x)\bigg |^b_a~=~F(b)-F(a)$