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Thread: Use [tex] and [/tex] tags NOT [tex] and [/tex] tags for latex.

  1. #16
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    Re: Use [tex] and [/tex] tags NOT [tex] and [/tex] tags for latex.

    \[\sqrt {{b^2} - 4ac} \]
    Last edited by mpx86; Jun 16th 2013 at 09:45 PM.
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  2. #17
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    Re: Use [tex] and [/tex] tags NOT [tex] and [/tex] tags for latex.

    am quite new to this forum and i have little idea on how to use the editor but please this is my question
    Please am stuck with the integration I kindly need assistance in solving this equation, I will really appreciate if anyone could help with the solution or a guide on what i should do

    [tex]C(N)=\int_{0}^{\infty}log(1+\frac{\rho}{a}z)\frac{ N\left(e^{-z}z^{y-1}\right)}{\left(y-1\right)!}\left(1-e^{-z}\sum_{i=0}^{y-1}\frac{z^{i}}{i!}\right)^{N-1}dz[\tex]
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  3. #18
    Member GLaw's Avatar
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    The closing tag should be [/TEX], not [\TEX].

    C(N)=\int_{0}^{\infty}log(1+\frac{\rho}{a}z)\frac{ N\left(e^{-z}z^{y-1}\right)}{\left(y-1\right)!}\left(1-e^{-z}\sum_{i=0}^{y-1}\frac{z^{i}}{i!}\right)^{N-1}dz

    Also it is better to write
    \log rather than log to indicate that it is an operator name rather than the product of three variables $l,o,g$.

    C(N)=\int_{0}^{\infty}\log(1+\frac{\rho}{a}z)\frac  { N\left(e^{-z}z^{y-1}\right)}{\left(y-1\right)!}\left(1-e^{-z}\sum_{i=0}^{y-1}\frac{z^{i}}{i!}\right)^{N-1}dz
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  4. #19
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    Re: Use [tex] and [/tex] tags NOT [tex] and [/tex] tags for latex.

    [/Tex]
    \int_1^e \dfrac{1}{x}dx=lne-ln1=1
    [/Tex]
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  5. #20
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    Re: Use [tex] and [/tex] tags NOT [tex] and [/tex] tags for latex.

    Quote Originally Posted by Loser66 View Post
    [/Tex]
    \int_1^e \dfrac{1}{x}dx=lne-ln1=1
    [/Tex]
    Don't use the / in the opening delimiter. Should be this to begin: [TEX]. So your equation is this:

    \int_1^e \dfrac{1}{x}dx=lne-ln1=1
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  6. #21
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    Re: Use [tex] and [/tex] tags NOT [tex] and [/tex] tags for latex.

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  7. #22
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    Re: Use [tex] and [/tex] tags NOT [tex] and [/tex] tags for latex.

    Quote Originally Posted by Mr.MathType View Post
    Don't use the / in the opening delimiter. Should be this to begin: [TEX]. So your equation is this:

    \int_1^e \dfrac{1}{x}dx=lne-ln1=1
    \$\int_1^e \dfrac{1}{x}dx=lne-ln1=1\$ using the dollar sign gives a better rendering.

    $\int_1^e \dfrac{1}{x}dx=lne-ln1=1$
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  8. #23
    Junior Member Mr.MathType's Avatar
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    Re: Use [tex] and [/tex] tags NOT [tex] and [/tex] tags for latex.

    Actually I just noticed something else that would make it look better: Code the log as \ln, not simply ln. So now we have either $\int_1^e {\frac{1}{x}dx} = \ln e - \ln 1 = 1$ or

    \int_1^e {\frac{1}{x}dx}  = \ln e - \ln 1 = 1,

    depending on whether it's inline or not.
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