Re: Use [tex] and [/tex] tags NOT [math] and [/math] tags for latex.

$\displaystyle \[\sqrt {{b^2} - 4ac} \]$

Re: Use [tex] and [/tex] tags NOT [math] and [/math] tags for latex.

am quite new to this forum and i have little idea on how to use the editor but please this is my question

Please am stuck with the integration I kindly need assistance in solving this equation, I will really appreciate if anyone could help with the solution or a guide on what i should do

[tex]C(N)=\int_{0}^{\infty}log(1+\frac{\rho}{a}z)\frac{ N\left(e^{-z}z^{y-1}\right)}{\left(y-1\right)!}\left(1-e^{-z}\sum_{i=0}^{y-1}\frac{z^{i}}{i!}\right)^{N-1}dz[\tex]

Re: Use [tex] and [/tex] tags NOT [math] and [/math] tags for latex.

[/Tex]

\int_1^e \dfrac{1}{x}dx=lne-ln1=1

[/Tex]

Re: Use [tex] and [/tex] tags NOT [tex] and [/tex] tags for latex.

Quote:

Originally Posted by

**Loser66** [/Tex]

\int_1^e \dfrac{1}{x}dx=lne-ln1=1

[/Tex]

Don't use the / in the opening delimiter. Should be this to begin: [TEX]. So your equation is this:

$\displaystyle \int_1^e \dfrac{1}{x}dx=lne-ln1=1$

Re: Use [tex] and [/tex] tags NOT [tex] and [/tex] tags for latex.

Re: Use [tex] and [/tex] tags NOT [tex] and [/tex] tags for latex.

Quote:

Originally Posted by

**Mr.MathType** Don't use the / in the opening delimiter. Should be this to begin: [TEX]. So your equation is this:

$\displaystyle \int_1^e \dfrac{1}{x}dx=lne-ln1=1$

\$\int_1^e \dfrac{1}{x}dx=lne-ln1=1\$ using the dollar sign gives a better rendering.

$\int_1^e \dfrac{1}{x}dx=lne-ln1=1$

Re: Use [tex] and [/tex] tags NOT [tex] and [/tex] tags for latex.

Actually I just noticed something else that would make it look better: Code the log as **\ln**, not simply **ln**. So now we have either $\int_1^e {\frac{1}{x}dx} = \ln e - \ln 1 = 1$ or

$\displaystyle \int_1^e {\frac{1}{x}dx} = \ln e - \ln 1 = 1$,

depending on whether it's inline or not.