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Math Help - Parenthesis Around Fraction - How Make Bigger

  1. #1
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    Question Parenthesis Around Fraction - How Make Bigger

    Given the following equation --

    \pm(\frac{1+i}{\sqrt2})=\sqrt{i}

    How can the parenthesis -- (. . . .) -- around fraction be made larger so as to encompass the entire fraction?
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  2. #2
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    Quote Originally Posted by DeanSchlarbaum View Post
    Given the following equation --

    \pm(\frac{1+i}{\sqrt2})=\sqrt{i}

    How can the parenthesis -- (. . . .) -- around fraction be made larger so as to encompass the entire fraction?
    \big( \big)
    \bigg( \bigg)
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    Hello, DeanSchlarbaum!

    Given the following equation: .
    \pm(\frac{1+i}{\sqrt2})=\sqrt{i}

    How can the parenthesis (. . . .) around a fraction be made larger?

    [math ]\pm \left( \frac{1+i}{\sqrt2} \right) \;=\; \sqrt{i}[/math ]

    . . \pm\left(\frac{1+i}{\sqrt2}\right)\;=\;\sqrt{i}



    This works for any size fraction:

    . .  \left[   \frac{\dfrac{1}{4}+\dfrac{2}{3}}{5 + \dfrac{1}{2}} \right]


    [math ] \left[ \frac{\dfrac{1}{4}+\dfrac{2}{3}}{5 + \dfrac{1}{2}} \right] [/math ]
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  4. #4
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    Quote Originally Posted by Soroban View Post
    Hello, DeanSchlarbaum!


    [math ]\pm \left( \frac{1+i}{\sqrt2} \right) \;=\; \sqrt{i}[/math ]

    . . \pm\left(\frac{1+i}{\sqrt2}\right)\;=\;\sqrt{i}



    This works for any size fraction:

    . .  \left[   \frac{\dfrac{1}{4}+\dfrac{2}{3}}{5 + \dfrac{1}{2}} \right]


    [math ] \left[ \frac{\dfrac{1}{4}+\dfrac{2}{3}}{5 + \dfrac{1}{2}} \right] [/math ]
    \left and \right are certainly very useful. But they sometimes make parentheses that are larger than you really want. For example, there are situations where something like \left(1+\sum_{n=1}^Nx_n^2\right)^{1/2}<\infty might be improved by writing it as \biggl(1+\sum_{n=1}^Nx_n^2\biggr)^{1/2}<\infty, or even \Bigl(1+\sum_{n=1}^Nx_n^2\Bigr)^{1/2}<\infty, using \biggl and \biggr (or \Bigl and \Bigr) instead of \left and \right.
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