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Thread: How do I make sums full size in cases?

  1. #1
    Senior Member
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    How do I make sums full size in cases?

    I.e. in the following, the sums are inline, but I'd like them larger.

    f(z)=\begin{cases}-\frac{1}{z-2}\sum_{n=0}^\infty \left(\frac{z-2}{2}\right)^2, & \text{for}~ |z-2|<2<br /> <br />
\\ \frac{2}{(z-2)^2} \sum_{n=0}^\infty \left(-\frac{2}{z-2}\right)^2, &\text{for}~|z-2|>2<br />
 \end{cases}

    Is it possible?
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  2. #2
    Super Member Failure's Avatar
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    Quote Originally Posted by scorpion007 View Post
    I.e. in the following, the sums are inline, but I'd like them larger.

    f(z)=\begin{cases}-\frac{1}{z-2}\sum_{n=0}^\infty \left(\frac{z-2}{2}\right)^2, & \text{for}~ |z-2|<2<br /> <br />
\\ \frac{2}{(z-2)^2} \sum_{n=0}^\infty \left(-\frac{2}{z-2}\right)^2, &\text{for}~|z-2|>2<br />
\end{cases}

    Is it possible?
    If you add \displaystyle to the two cases, you get this:

    f(z)=\begin{cases}\displaystyle-\frac{1}{z-2}\sum_{n=0}^\infty \left(\frac{z-2}{2}\right)^2, & \text{for}~ |z-2|<2<br /> <br />
\\ \displaystyle\frac{2}{(z-2)^2} \sum_{n=0}^\infty \left(-\frac{2}{z-2}\right)^2, &\text{for}~|z-2|>2<br />
\end{cases}
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  3. #3
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    Thanks a lot!
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