Results 1 to 4 of 4

Math Help - [SOLVED] \frac with \choose

  1. #1
    Member courteous's Avatar
    Joined
    Aug 2008
    From
    big slice of heaven
    Posts
    206

    [SOLVED] \frac with \choose

    How can one present fraction with combinations above and below?

    For example, \frac{ 4\choose 4 48\choose 9 }{ 52\choose 13 } gives this: \frac{ 4\choose 4  48\choose 9 }{ 52\choose 13 }

    I've already searched for "choose" in "Latex Help Forum".
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor

    Joined
    Aug 2006
    Posts
    18,706
    Thanks
    1637
    Awards
    1
    Quote Originally Posted by courteous View Post
    How can one present fraction with combinations above and below?

    For example, \frac{ 4\choose 4 48\choose 9 }{ 52\choose 13 } gives this: \frac{ {4 \choose 4}{48 \choose 9} }{ 52 \choose 13 }

    I've already searched for "choose" in "Latex Help Forum".
    I would use \binom{}{}
    [tex]\frac{\displaystyle\binom{4}{4}\binom{48}{9}}{\dis playstyle\binom{52}{13}}[/tex]

    \frac{\displaystyle\binom{4}{4}\binom{48}{9}}{\dis  playstyle\binom{52}{13}}
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
    Posts
    11,746
    Thanks
    648
    Hello, courteous!

    How can one present fraction with combinations above and below?

    For example, \frac{ 4\choose 4 48\choose 9 }{ 52\choose 13 } gives this: \frac{ 4\choose 4  48\choose 9 }{ 52\choose 13 }

    The "choose" function must be enclosed in braces: .{6 \choose 2}


    The code looks like this:

    \frac{ {4\choose4} {48\choose9} } { {52\choose13} }

    . . . \frac{{4\choose4}{48\choose9}}{{52\choose13}}



    As Plato pointed out, it can be enlarged
    . . by inserting \displaystyle in the numerator and denominator.


    \frac{\displaystyle {4\choose4} {48\choose9} } {\displaystyle {52\choose13} }

    . . . \frac{\displaystyle{4\choose4}{48\choose9}}{\displ  aystyle{52\choose13}}

    Follow Math Help Forum on Facebook and Google+

  4. #4
    Member courteous's Avatar
    Joined
    Aug 2008
    From
    big slice of heaven
    Posts
    206
    \frac{{4\choose 4}{48\choose 9}}{{52\choose 13}}
    It works!
    Though I'm pretty sure I tried curly braces around \choose before.

    Thank you both.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 6
    Last Post: March 26th 2011, 06:05 AM
  2. [SOLVED] arg(\frac{1}{z})
    Posted in the Differential Geometry Forum
    Replies: 8
    Last Post: September 24th 2010, 04:18 PM
  3. [SOLVED] arg(z)=\frac{\pi}{4}
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: September 5th 2010, 04:50 PM
  4. Replies: 1
    Last Post: January 7th 2010, 09:53 AM
  5. Replies: 3
    Last Post: November 17th 2009, 07:18 PM

Search Tags


/mathhelpforum @mathhelpforum